Math Problem Statement

f(z)=(2x-x^3+3xy^2)+i(2y-3x^2y+y^3+c) .find f'(z) and express in terms of x,y in complex analysis

Solution

To find the derivative f(z)f'(z) of the complex-valued function f(z)=u(x,y)+iv(x,y)f(z) = u(x, y) + i v(x, y), we use the Cauchy-Riemann equations and the formula:

f(z)=ux+ivx,f'(z) = \frac{\partial u}{\partial x} + i \frac{\partial v}{\partial x}, provided the Cauchy-Riemann equations hold. Let us compute step-by-step.


Step 1: Split f(z)f(z) into real and imaginary parts

Given: f(z)=(2xx3+3xy2)+i(2y3x2y+y3+c),f(z) = \big( 2x - x^3 + 3xy^2 \big) + i \big( 2y - 3x^2y + y^3 + c \big), where: u(x,y)=2xx3+3xy2,v(x,y)=2y3x2y+y3+c.u(x, y) = 2x - x^3 + 3xy^2, \quad v(x, y) = 2y - 3x^2y + y^3 + c.


Step 2: Compute partial derivatives

Derivatives of u(x,y)u(x, y):

ux=23x2+3y2,uy=6xy.\frac{\partial u}{\partial x} = 2 - 3x^2 + 3y^2, \quad \frac{\partial u}{\partial y} = 6xy.

Derivatives of v(x,y)v(x, y):

vx=6xy,vy=23x2+3y2.\frac{\partial v}{\partial x} = -6xy, \quad \frac{\partial v}{\partial y} = 2 - 3x^2 + 3y^2.


Step 3: Check the Cauchy-Riemann equations

The Cauchy-Riemann equations are: ux=vy,uy=vx.\frac{\partial u}{\partial x} = \frac{\partial v}{\partial y}, \quad \frac{\partial u}{\partial y} = -\frac{\partial v}{\partial x}.

  1. For the first equation: ux=23x2+3y2,vy=23x2+3y2.\frac{\partial u}{\partial x} = 2 - 3x^2 + 3y^2, \quad \frac{\partial v}{\partial y} = 2 - 3x^2 + 3y^2. This holds.

  2. For the second equation: uy=6xy,vx=(6xy)=6xy.\frac{\partial u}{\partial y} = 6xy, \quad -\frac{\partial v}{\partial x} = -(-6xy) = 6xy. This also holds.

Thus, the Cauchy-Riemann equations are satisfied.


Step 4: Compute f(z)f'(z)

Using: f(z)=ux+ivx,f'(z) = \frac{\partial u}{\partial x} + i \frac{\partial v}{\partial x}, we substitute: ux=23x2+3y2,vx=6xy.\frac{\partial u}{\partial x} = 2 - 3x^2 + 3y^2, \quad \frac{\partial v}{\partial x} = -6xy.

Thus: f(z)=(23x2+3y2)+i(6xy).f'(z) = \big( 2 - 3x^2 + 3y^2 \big) + i \big( -6xy \big).


Final Answer:

f(z)=(23x2+3y2)6xyi.f'(z) = (2 - 3x^2 + 3y^2) - 6xy i.

Let me know if you'd like further clarifications or additional examples! 😊


Related Questions:

  1. What are the Cauchy-Riemann equations, and how do they ensure analyticity?
  2. How do we interpret f(z)f'(z) geometrically in complex analysis?
  3. What is the significance of a function satisfying the Cauchy-Riemann equations?
  4. How do partial derivatives relate to the real and imaginary components of f(z)f(z)?
  5. What happens if cc in the given function is not constant?

Tip: Always verify the Cauchy-Riemann equations before assuming a function is differentiable in the complex sense!

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Math Problem Analysis

Mathematical Concepts

Complex Analysis
Differentiation
Cauchy-Riemann Equations
Partial Derivatives

Formulas

f'(z) = ∂u/∂x + i ∂v/∂x
Cauchy-Riemann equations: ∂u/∂x = ∂v/∂y, ∂u/∂y = -∂v/∂x

Theorems

Cauchy-Riemann Equations

Suitable Grade Level

Undergraduate