Math Problem Statement
Procedure DFS(graph, parents, sequence, i) sequence = sequence ++ [i] foreach j in columns(graph){ if(graph[i][j] == 1 and not(isKey(parents, j))){ parents[j] = i parents, sequence = DFS(graph, parents, sequence, j) } } return(parents, sequence) End DFS
Solution
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Math Problem Analysis
Mathematical Concepts
Graph Theory
Depth-First Search (DFS)
Adjacency Matrix
Formulas
-
Theorems
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Suitable Grade Level
Advanced
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