Math Problem Statement

Calculate the demand functions of x1 and x2 for the following utility function U1(x1, x2) = log x1 + 2 log x2, given income I and prices p1 and p2. Writing a demand function is tantamount to express demand for good x as a function of px, I, and perhaps py in the case of a rational consumer. Without further information, you must:

  1. Write the budget constraint I as a function of quantities and prices.
  2. Write the Lagrangian equation.
  3. Compute the first derivative of L with respect to x1, x2, and λ.
  4. Express xi as a function of income I and, if relevant, xj , where j ̸= i and i, j ∈ {1, 2}.

Solution

We are tasked with calculating the demand functions for x1x_1 and x2x_2 for the utility function:

U(x1,x2)=log(x1)+2log(x2)U(x_1, x_2) = \log(x_1) + 2\log(x_2)

given income II and prices p1p_1 and p2p_2. We will proceed through the steps outlined to compute the demand functions.

Step 1: Write the Budget Constraint

The budget constraint is the equation that reflects the consumer's total expenditure, given by:

p1x1+p2x2=Ip_1 x_1 + p_2 x_2 = I

where:

  • p1p_1 is the price of good 1,
  • p2p_2 is the price of good 2,
  • II is the total income,
  • x1x_1 and x2x_2 are the quantities of goods 1 and 2, respectively.

Step 2: Write the Lagrangian Equation

To solve the optimization problem, we use the method of Lagrange multipliers. The Lagrangian is:

L(x1,x2,λ)=log(x1)+2log(x2)+λ(Ip1x1p2x2)\mathcal{L}(x_1, x_2, \lambda) = \log(x_1) + 2\log(x_2) + \lambda (I - p_1 x_1 - p_2 x_2)

where λ\lambda is the Lagrange multiplier.

Step 3: Compute the First Derivatives

We now compute the first-order conditions by taking the partial derivatives of L\mathcal{L} with respect to x1x_1, x2x_2, and λ\lambda, and then setting them equal to zero.

Derivative with respect to x1x_1:

Lx1=1x1λp1=0\frac{\partial \mathcal{L}}{\partial x_1} = \frac{1}{x_1} - \lambda p_1 = 0 λ=1p1x1\Rightarrow \lambda = \frac{1}{p_1 x_1}

Derivative with respect to x2x_2:

Lx2=2x2λp2=0\frac{\partial \mathcal{L}}{\partial x_2} = \frac{2}{x_2} - \lambda p_2 = 0 λ=2p2x2\Rightarrow \lambda = \frac{2}{p_2 x_2}

Derivative with respect to λ\lambda (enforces the budget constraint):

Lλ=Ip1x1p2x2=0\frac{\partial \mathcal{L}}{\partial \lambda} = I - p_1 x_1 - p_2 x_2 = 0 p1x1+p2x2=I\Rightarrow p_1 x_1 + p_2 x_2 = I

Step 4: Express x1x_1 and x2x_2 as Functions of Income and Prices

From the first two derivatives, we now have two expressions for λ\lambda:

  1. λ=1p1x1\lambda = \frac{1}{p_1 x_1}
  2. λ=2p2x2\lambda = \frac{2}{p_2 x_2}

Equating these two expressions:

1p1x1=2p2x2\frac{1}{p_1 x_1} = \frac{2}{p_2 x_2}

Solving for x1x_1 in terms of x2x_2:

x2=2p1p2x1x_2 = \frac{2 p_1}{p_2} x_1

Now, substitute this into the budget constraint p1x1+p2x2=Ip_1 x_1 + p_2 x_2 = I:

p1x1+p2(2p1p2x1)=Ip_1 x_1 + p_2 \left( \frac{2 p_1}{p_2} x_1 \right) = I p1x1+2p1x1=Ip_1 x_1 + 2 p_1 x_1 = I 3p1x1=I3 p_1 x_1 = I x1=I3p1x_1 = \frac{I}{3 p_1}

Now, substitute x1x_1 into the expression for x2x_2:

x2=2p1p2I3p1=2I3p2x_2 = \frac{2 p_1}{p_2} \cdot \frac{I}{3 p_1} = \frac{2 I}{3 p_2}

Demand Functions

Thus, the demand functions for goods x1x_1 and x2x_2 are:

x1=I3p1x_1 = \frac{I}{3 p_1} x2=2I3p2x_2 = \frac{2 I}{3 p_2}

These are the Marshallian demand functions for goods 1 and 2.


Would you like further details on any part of this solution? Here are five related questions to expand on this topic:

  1. How do changes in prices p1p_1 and p2p_2 affect the demand for x1x_1 and x2x_2?
  2. What are the elasticities of demand for x1x_1 and x2x_2?
  3. Can we derive the indirect utility function from these demand functions?
  4. How would the demand functions change if the utility function had a different form (e.g., CES utility)?
  5. How do we interpret the Lagrange multiplier λ\lambda in this context?

Tip: When solving utility maximization problems, always check that the first-order conditions satisfy the budget constraint, as this ensures optimal consumption.

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Utility Maximization
Lagrangian Multipliers
Demand Functions
Logarithmic Utility

Formulas

Budget constraint: p1 * x1 + p2 * x2 = I
Lagrangian: L(x1, x2, λ) = log(x1) + 2 log(x2) + λ(I - p1 * x1 - p2 * x2)
First-order conditions: ∂L/∂x1 = 1/x1 - λ * p1 = 0, ∂L/∂x2 = 2/x2 - λ * p2 = 0
Demand functions: x1 = I / (3 * p1), x2 = 2 * I / (3 * p2)

Theorems

First-order Condition for Utility Maximization
Marshallian Demand Functions

Suitable Grade Level

Undergraduate Economics