To determine the degree of the function and whether it is quadratic, let's first simplify the expression for $f(t)$:

$f(t) = (t + 6)^2 - t^2$

Step 1: Expand the terms

First, expand $(t + 6)^2$: $(t + 6)^2 = t^2 + 12t + 36$

Now substitute this into the original function: $f(t) = (t^2 + 12t + 36) - t^2$

Step 2: Simplify the expression

Simplify by canceling out the $t^2$ terms: $f(t) = 12t + 36$

Step 3: Determine the degree of the function

The simplified expression is $f(t) = 12t + 36$. This is a linear function because the highest power of $t$ is 1. Therefore, the degree of the function is 1.

Conclusion:

• The degree of the function is 1.
• It is not quadratic (a quadratic function has a degree of 2).

Would you like more details or have any questions?

Here are 5 related questions to expand on this topic:

1. What is the general form of a quadratic function?
2. How can you determine the degree of a polynomial?
3. What are the characteristics