We need to evaluate the integral of the function \( (x^2 + 4)e^{-x} \) from 0 to 2. This is a definite integral, and we can solve it using integration by parts. Let's break it down step by step.

The integral to evaluate is:

\[
I = \int_0^2 (x^2 + 4) e^{-x} \, dx
\]

### Step 1: Split the integral

We can break the integral into two parts:

\[
I = \int_0^2 x^2 e^{-x} \, dx + \int_0^2 4 e^{-x} \, dx
\]

Let's solve these two integrals separately.

### Step 2: Solving the first integral \( \int_0^2 x^2 e^{-x} \, dx \)

We use integration by parts. Let’s first choose the parts:
- Let \( u = x^2 \), which means \( du = 2x \, dx \).
- Let \( dv = e^{-x} \, dx \), so \( v = -e^{-x} \).

Using the integration by parts formula:

\[
\int u \, dv = uv - \int v \, du
\]

Now, apply this to \( \int x^2 e^{-x} \, dx \):

\[
\int x^2 e^{-x} \, dx = -x^2 e^{-x} \Big|_0^2 + 2 \int x e^{-x} \, dx
\]

For \( \int x e^{-x} \, dx \), apply integration by parts again:
- Let \( u = x \), so \( du = dx \).
- Let \( dv = e^{-x} \, dx \), so \( v = -e^{-x} \).

\[
\int x e^{-x} \, dx = -x e^{-x} \Big|_0^2 + \int e^{-x} \, dx
\]
\[
\int x e^{-x} \, dx = -x e^{-x} \Big|_0^2 + e^{-x} \Big|_0^2
\]

Evaluating both integrals at the limits:

\[
-x e^{-x} \Big|_0^2 = -(2e^{-2} - 0e^{-0}) = -2e^{-2}
\]
\[
e^{-x} \Big|_0^2 = e^{-2} - e^{0} = e^{-2} - 1
\]

Thus:

\[
\int x e^{-x} \, dx = -2e^{-2} + (e^{-2} - 1) = -e^{-2} - 1
\]

Now, substitute back into the expression for \( \int x^2 e^{-x} \, dx \):

\[
\int x^2 e^{-x} \, dx = -x^2 e^{-x} \Big|_0^2 + 2(-e^{-2} - 1)
\]
\[
-x^2 e^{-x} \Big|_0^2 = -(4e^{-2} - 0e^{-0}) = -4e^{-2}
\]

Thus:

\[
\int_0^2 x^2 e^{-x} \, dx = -4e^{-2} + 2(-e^{-2} - 1) = -4e^{-2} - 2e^{-2} - 2 = -6e^{-2} - 2
\]

### Step 3: Solving the second integral \( \int_0^2 4 e^{-x} \, dx \)

This is a straightforward integral:

\[
\int 4 e^{-x} \, dx = -4 e^{-x} \Big|_0^2 = -4(e^{-2} - e^{0}) = -4(e^{-2} - 1)
\]
\[
= 4(1 - e^{-2})
\]

### Step 4: Combine the results

Now, add the two integrals together:

\[
I = (-6e^{-2} - 2) + 4(1 - e^{-2})
\]
\[
I = -6e^{-2} - 2 + 4 - 4e^{-2}
\]
\[
I = 2 - 10e^{-2}
\]

Thus, the value of the definite integral is:

\[
\boxed{2 - 10e^{-2}}
\]

Would you like more details on any of the steps, or have any questions?

### Follow-up questions:
1. What is the integration by parts method, and how is it derived?
2. How do definite integrals differ from indefinite integrals?
3. What are common strategies for dealing with exponential functions in integrals?
4. Can you explain why we chose \( u = x^2 \) in the first integration by parts step?
5. How would this integral change if we replaced \( e^{-x} \) with \( e^{x} \)?

### Tip:
Always double-check your integration limits when calculating definite integrals to avoid sign errors in your final result.

This solution explains how to evaluate the definite integral of (x^2 + 4)e^-x from 0 to 2. It uses integration by parts to break down the integral and exponential functions. Suitable for advanced high school students or early college learners, covering key calculus concepts.

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