Math Problem Statement
∫ π 0 esin(t) cos(t) sin(t)dt
Solution
We are asked to evaluate the definite integral:
To solve this, notice that we can rewrite the product of as:
Thus, the integral becomes:
Now let's simplify this integral and examine potential substitutions:
- Set , which implies .
- The limits change accordingly: when , , and when , .
- The integral becomes more manageable. However, due to the symmetry of sine over the interval, the result will be zero, since the integrand is an odd function (because of the ) over a symmetric interval from to .
Thus, the value of the integral is:
Would you like more details on any of the steps?
Here are 5 questions to consider:
- What are the properties of definite integrals that help simplify symmetric intervals?
- How can trigonometric identities simplify integrals involving sine and cosine?
- What other techniques could be applied to solve integrals involving exponentials and trigonometric functions?
- Why does the function being odd lead to the integral being zero?
- How would the integral change if the limits were different?
Tip: Symmetry in integrals is a powerful tool—always check if the integrand is odd or even when dealing with symmetric limits.
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Math Problem Analysis
Mathematical Concepts
Calculus
Definite Integrals
Trigonometric Substitution
Symmetry in Functions
Formulas
cos(t) sin(t) = 1/2 sin(2t)
Integral of an odd function over symmetric limits equals zero
Theorems
Symmetry property of definite integrals
Odd and even function properties
Suitable Grade Level
University Level (Calculus II or higher)
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