Math Problem Statement

Solve the question

Solve the following questions: 1. A cross section of a cylindrical cistern is shown. What is the volume of the cistern? 2. How many cubic yards of earth are excavated for a concrete cistern with an outside diameter of 9'6" and a depth of 10'0", with an 18-inch allowance for form work?

Solution

Let's tackle each question in the "Review Problems" section step-by-step.

Problem 1:

We are given:

  • Diameter of the cistern = 4'0" (or 4 feet)
  • Therefore, the radius r=42=2r = \frac{4}{2} = 2 feet.

Using the volume formula for a cylinder: V=πr2hV = \pi r^2 h Substitute the values:

  • Radius r=2r = 2 feet
  • Height h=8h = 8 feet

Using π=3.1416\pi = 3.1416: V=3.1416×22×8V = 3.1416 \times 2^2 \times 8 V=3.1416×4×8V = 3.1416 \times 4 \times 8 V=3.1416×32V = 3.1416 \times 32 V100.53 cubic feetV \approx 100.53 \text{ cubic feet}

So, the volume of the cistern is approximately 100.53 cubic feet.


Problem 2:

For this problem:

  • Outside diameter = 9'6" = 9.5 feet
  • Outside depth = 10'0" = 10 feet
  • Allowance for form work (walls) is 18 inches (1.5 feet), meaning we’ll reduce 1.5 feet from the diameter and depth for the actual inside measurements.

Step 1: Find the effective inner diameter and height.

  • Effective inner diameter = 9.5 - 2(1.5) = 6.5 feet
    • Radius r=6.52=3.25r = \frac{6.5}{2} = 3.25 feet
  • Effective inner depth (height) = 10 - 1.5 = 8.5 feet

Step 2: Calculate the volume.

Using the formula: V=πr2hV = \pi r^2 h where:

  • π=3.1416\pi = 3.1416
  • r=3.25r = 3.25
  • h=8.5h = 8.5

V=3.1416×(3.25)2×8.5V = 3.1416 \times (3.25)^2 \times 8.5 V=3.1416×10.5625×8.5V = 3.1416 \times 10.5625 \times 8.5 V282.74 cubic feetV \approx 282.74 \text{ cubic feet}

Step 3: Convert to cubic yards.

Since there are 27 cubic feet in a cubic yard: 282.742710.47 cubic yards\frac{282.74}{27} \approx 10.47 \text{ cubic yards}

So, the amount of earth to be excavated is approximately 10.47 cubic yards.


Would you like a deeper breakdown of these calculations or have any specific questions?

Related Questions:

  1. How would you calculate the volume of a cylinder if the radius and height were given in different units (e.g., inches and feet)?
  2. If the cistern in Problem 1 had an irregular cross-section, how would the volume formula change?
  3. How does the volume calculation change if you need to account for a slanted top or bottom in a cylinder?
  4. What is the impact of using different approximations for π\pi on the volume results?
  5. How would adding a hemispherical dome on top of the cistern affect the total volume?

Tip: Always ensure units are consistent throughout the calculation to avoid conversion errors.

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Math Problem Analysis

Mathematical Concepts

Volume Calculation
Geometry of Cylinders
Unit Conversion

Formulas

V = πr^2h
Conversion from cubic feet to cubic yards

Theorems

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Suitable Grade Level

Grades 8-10