The image you uploaded describes a three-phase electrical circuit with a voltage $U_d = 220V$. The resistance values for the three phases are:

• $R_A = 12.5 \, \Omega$
• $R_B = 12.5 \, \Omega$
• $R_C = 25 \, \Omega$

The task is to calculate the current in each phase, $I_A$, $I_B$, and $I_C$, and identify which of the given options matches the correct current values.

To solve this, we can use Ohm’s Law, which is:

$I = \frac{U}{R}$

Where:

• $I$ is the current,
• $U$ is the voltage,
• $R$ is the resistance.

Given the voltage $U = 220V$, we can calculate the current for each phase as follows:

1. For Phase A: $I_A = \frac{220}{12.5} = 17.6 \, \text{A}$

2. For Phase B: $I_B = \frac{220}{12.5} = 17.6 \, \text{A}$

3. For Phase C: $I_C = \frac{220}{25} = 8.8 \, \text{A}$

Therefore, the current values for each phase are:

• $I_A = 17.6 \, \text{A}$
• $I_B = 17.6 \, \text{A}$
• $I_C = 8.8 \, \text{A}$

However, none of the options provided exactly match these current values. Could you clarify if the resistances are part of a more complex circuit (such as if the phases are connected in series or parallel) or if there might be another component affecting the current?

Let me know if you need further details or clarification!

Related questions:

1. How does the current change if the resistances are connected in series?
2. What happens to the current if the voltage is increased to 240V instead of 220V?
3. How would the current change if the resistances for all three phases were equal?
4. What is the total current in the system if these phases are connected in parallel?
5. How would the power consumed in each phase change with different resistances?

Tip: When dealing with resistances in parallel or series in a three-phase system, remember that the total equivalent resistance affects the current across each phase. Always check the configuration to determine how the current divides.