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This circuit consists of a current source (8 A) in series with two resistors: \(1 \, \Omega\) and \(3 \, \Omega\). To calculate the current through the \(3 \, \Omega\) resistor, we first need to understand that this is a series circuit. In a series circuit, the current is the same through all components.

### Steps:
1. Since the current source provides \(8 \, \text{A}\), and all elements are in series, the same \(8 \, \text{A}\) flows through the \(1 \, \Omega\) and the \(3 \, \Omega\) resistors.
2. Therefore, the current through the \(3 \, \Omega\) resistor is also **\(8 \, \text{A}\)**.

No further calculation is required, as the series arrangement ensures that all components have the same current.

Would you like more details or have any further questions?

Here are 5 related questions for practice:
1. What is the voltage drop across the \(3 \, \Omega\) resistor?
2. What is the total resistance in the circuit?
3. What is the voltage drop across the \(1 \, \Omega\) resistor?
4. How would the current change if the \(3 \, \Omega\) resistor was replaced with a \(6 \, \Omega\) resistor?
5. What happens to the total current if a parallel branch is added?

**Tip:** In series circuits, the current remains the same across all components, but the voltage divides across each resistor based on their resistances.

Calculate the current through 3Ω resistor.

Learn how to calculate the current through a 3Ω resistor in a series circuit with a total current of 8A. This problem explores key electrical circuit concepts like Ohm's Law and current in series circuits. Suitable for students in Grades 9-12.

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