The question in the image asks to find the value of $\sqrt[3]{27}$, which is the cube root of 27.

Solution:

The cube root of a number $x$ is a number $y$ such that $y^3 = x$.

1. Start with $27$:
   We need to find $y$ such that $y^3 = 27$.

2. Test simple values:

   • $1^3 = 1$ (too small)
   • $2^3 = 8$ (still too small)
   • $3^3 = 27$ (perfect!)

3. Therefore, $\sqrt[3]{27} = 3$.

Final Answer:

The value is 3.

Let me know if you want a detailed explanation or have any questions!

Here are 5 related questions to explore:

1. What is the cube root of 64?
2. How do you compute higher roots like $\sqrt[4]{81}$?
3. How does the cube root differ from the square root?
4. Can negative numbers have real cube roots?
5. What are practical applications of cube roots in real life?

Tip: Cube roots are often used in volume-related problems, as the cube of a side length gives the volume of a cube.