It seems like you're trying to write the equation for $y$ in terms of the cube root, but there are some issues with the notation. I believe you mean the following:

$y = \sqrt[3]{x - 3} + 5$

Where the cube root of $(x - 3)$ is added to 5.

If this is correct, here's how the equation works:

1. The expression inside the cube root is $x - 3$.
2. You take the cube root of that expression.
3. Finally, you add 5 to the result.

Would you like to see an example, or need help solving for $x$ or $y$ given specific values?

Also, if you want further clarification or detailed steps, feel free to ask.

Related questions:

1. How do you solve for $x$ when $y$ is given?
2. What is the graph of this equation like?
3. How do transformations (like adding 5) affect the cube root function?
4. How do cube roots differ from square roots in terms of behavior?
5. Can you explain how to combine cube roots with other algebraic expressions?

Tip: When working with cube roots, remember that the cube root of a negative number is also real, unlike the square root where negative numbers produce imaginary results!