Math Problem Statement
Suppose you owe $16,000 on a credit card that carries an APR of 24%. Because the balance is so high, you choose to stop charging and pay off the card. You can afford to make only the minimum monthly payment, which is 5% of the balance. Then your balance after t months is given by B = 16,000(1.02 ✕ 0.95)t dollars. How many payments will you have to make to get the balance below $400? (Enter the smallest such number of payments as an integer.)
Solution
We are given the formula for the balance after months:
First, simplify the expression inside the parentheses:
So the balance formula becomes:
We want to find the smallest number of months, , such that the balance is below $400. This means we need to solve the inequality:
Step 1: Divide both sides by 16,000
Simplifying the right-hand side:
Step 2: Take the natural logarithm of both sides
Taking the natural logarithm of both sides helps to solve for :
Using the logarithmic property , we get:
Step 3: Solve for
Now divide both sides by . Since is negative, we must reverse the inequality:
Using a calculator:
Now compute :
Since must be an integer, the smallest number of months is .
Conclusion:
You will need to make 118 payments to get the balance below $400.
Would you like more details on the steps, or do you have any further questions?
Here are 5 related questions to consider:
- What happens if you increase your monthly payment slightly?
- How does the interest rate (APR) affect the total time to pay off the debt?
- How would the formula change if the minimum payment were a fixed dollar amount rather than a percentage?
- What is the total amount of money paid over 118 months?
- How does compound interest factor into long-term debt repayment?
Tip: Paying more than the minimum monthly payment will significantly reduce the time it takes to pay off a debt.
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Math Problem Analysis
Mathematical Concepts
Exponential Decay
Inequalities
Logarithms
Formulas
B = 16,000(0.969)^t
t > ln(0.025) / ln(0.969)
Theorems
Logarithmic Properties
Exponential Growth/Decay
Suitable Grade Level
Grades 10-12
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