Math Problem Statement
Find the number of integers between 1 and 10,000 inclusive which are divisible by 3 and 5, but not by either 7 or 11.
Solution
To solve the problem, we need to use principles of set theory and inclusion-exclusion. Let's denote:
- , the total range of integers.
- : Integers divisible by 3.
- : Integers divisible by 5.
- : Integers divisible by 7.
- : Integers divisible by 11.
We are tasked to find integers divisible by both 3 and 5 (i.e., ) but not divisible by or . Mathematically:
Step 1: Total numbers divisible by 15
The numbers divisible by 15 are:
Step 2: Numbers divisible by both 15 and 7
The least common multiple (LCM) of and is . The count is:
Step 3: Numbers divisible by both 15 and 11
The LCM of and is . The count is:
Step 4: Numbers divisible by 15, 7, and 11
The LCM of , , and is . The count is:
Step 5: Inclusion-Exclusion to find
The numbers divisible by and or are:
Substitute the values:
Step 6: Subtract from total numbers divisible by 15
The count of integers divisible by but not or is:
Substitute the values:
Final Answer:
The number of integers between 1 and 10,000 inclusive that are divisible by 3 and 5 but not by 7 or 11 is:
Let me know if you want a detailed breakdown or additional examples! 😊
- How does inclusion-exclusion work in set problems?
- Can we generalize this approach to other divisors?
- What is the importance of calculating LCM in such problems?
- How do you interpret modular arithmetic in divisibility rules?
- What if the range was extended to a different number, say 50,000?
Tip: For large ranges, writing modular rules as functions helps automate the calculations!
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Math Problem Analysis
Mathematical Concepts
Set Theory
Inclusion-Exclusion Principle
Divisibility
Least Common Multiple (LCM)
Formulas
|A ∩ B| = ⌊n / LCM(3, 5)⌋
|A ∩ B ∩ C| = ⌊n / LCM(15, 7)⌋
|A ∩ B ∩ D| = ⌊n / LCM(15, 11)⌋
|A ∩ B ∩ C ∩ D| = ⌊n / LCM(15, 7, 11)⌋
|A ∩ B \ (C ∪ D)| = |A ∩ B| - |A ∩ B ∩ (C ∪ D)|
Theorems
Inclusion-Exclusion Principle
Suitable Grade Level
Grades 9-12
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