https://file.aiquickdraw.com/mathbot/file/1726009603053aovngviy.jpg

The problem in the image asks us to calculate the cost of poblano peppers based on a proportional relationship between pounds and price, and the associated graph shown on the right.

From the graph, we can observe the following:
- 3 pounds of peppers cost $9.
- 6 pounds of peppers cost $18.

This indicates that the relationship is proportional, meaning the cost per pound is constant.

### Step 1: Determine the unit rate (cost per pound).
We can use the data from the graph to find the cost for 1 pound.

\[
\text{Cost per pound} = \frac{9 \text{ dollars}}{3 \text{ pounds}} = 3 \text{ dollars per pound}.
\]

### Step 2: Calculate the cost for 1 pound.
From the unit rate, 1 pound of peppers costs $3.

### Step 3: Calculate the cost for 3.5 pounds.
To find the cost for 3.5 pounds, we multiply the unit rate by 3.5.

\[
\text{Cost for 3.5 pounds} = 3 \times 3.5 = 10.5 \text{ dollars}.
\]

### Final Answer:
- **1 pound** of peppers costs **$3**.
- **3.5 pounds** of peppers cost **$10.50**.

Would you like more details on any of the steps or further explanation? 

Here are some related questions to expand on:
1. What is the definition of a proportional relationship?
2. How would you graph a proportional relationship?
3. Can you explain how to check if two quantities are proportional?
4. How does the unit rate help in solving real-world problems?
5. What are other examples where proportional relationships are used?

**Tip**: Always check for the unit rate first when dealing with proportional relationships.

Ignacio is making chiles en nogada to celebrate Mexican Independence Day with his family. Ignacio needs to buy poblano peppers. The local market sells poblano peppers by the pound. How much will 1 pound of peppers cost? How much will 3.5 pounds of peppers cost?

Learn how to calculate the cost of poblano peppers per pound and for 3.5 pounds using proportional relationships. This problem helps students understand unit rates and apply multiplication to solve real-world problems.

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