Math Problem Statement
HELP ME SOLVE
Solution
To solve this problem, let’s go through it step-by-step.
Given:
- A rectangular field with three walls of fencing, with the fourth side against the gym wall.
- The area of the field is .
- The cost of fencing is $89 per foot.
Goal:
Minimize the fencing cost while maintaining the area at 360,000 ft².
Step 1: Define Variables
Let:
- = length of the side parallel to the gym wall (no fencing needed here).
- = width of the field, which will have fencing.
Step 2: Set Up the Area Equation
The area of the rectangle is given by: Thus, we can express in terms of :
Step 3: Set Up the Fencing Cost Function
Since only three sides need fencing (two widths and one length ), the total length of fencing required is: Substitute from the area equation:
Step 4: Formulate the Cost Function
The cost in dollars is: Expanding this:
Step 5: Differentiate the Cost Function with Respect to and Find Critical Points
To minimize , we take the derivative of with respect to and set it equal to zero.
-
Differentiate with respect to :
-
Set to find the critical point: Solving for :
-
Substitute back into the area equation to find :
Step 6: Calculate the Total Cost
Now that we have the dimensions:
- ft
- ft
The total fencing length needed is:
The cost is:
Final Answer:
The least amount of money needed is $151,438.45.
Would you like further details on any of these steps, or have any questions?
Related Questions:
- What is the general method for minimizing costs in fencing problems?
- How would the cost change if the price per foot of fencing increased?
- What if the field area were different? How would that affect the dimensions?
- Why do we only differentiate with respect to in this problem?
- How can we verify that this solution gives the minimum cost?
Tip:
In optimization problems, always check if critical points provide a minimum or maximum by evaluating endpoints or using the second derivative test.
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Math Problem Analysis
Mathematical Concepts
Optimization
Differentiation
Cost Minimization
Area Calculation
Formulas
Area = x * y
Cost = 89 * (x + 2y)
Differentiation of Cost with respect to y
Theorems
Optimization in Calculus
Critical Points for Minimization
Suitable Grade Level
Grades 10-12