Math Problem Statement

The length, breadth, and height of a rectangular room are 13 ft, 12 ft, and 10 ft, respectively. There are 2 windows of size 3 ft × 4 ft and a door of size 3 ft × 6 ft. How much does it cost to paint the four walls and ceiling excluding the door and windows at the rate of Rs. 40 per square foot? By how much will the total cost of painting increase if the rate is increased by 25%?

Solution

The problem involves calculating the cost of painting a rectangular room. Let's solve it step by step.

Given Data:

  • Room dimensions: Length =13ft= 13 \, \text{ft}, Breadth =12ft= 12 \, \text{ft}, Height =10ft= 10 \, \text{ft}.
  • There are 2 windows of size 3ft×4ft3 \, \text{ft} \times 4 \, \text{ft} and 1 door of size 3ft×6ft3 \, \text{ft} \times 6 \, \text{ft}.
  • Cost of painting is Rs. 40 per square foot.

Part (a):

We are asked to find the cost of painting the four walls and the ceiling, excluding the areas of the door and windows.

Step 1: Total Area of the Four Walls

The total surface area of the four walls can be calculated as: Wall Area=2×(L×H)+2×(B×H)\text{Wall Area} = 2 \times (L \times H) + 2 \times (B \times H) where LL is the length, BB is the breadth, and HH is the height.

Wall Area=2×(13×10)+2×(12×10)=2×130+2×120=260+240=500sq ft\text{Wall Area} = 2 \times (13 \times 10) + 2 \times (12 \times 10) = 2 \times 130 + 2 \times 120 = 260 + 240 = 500 \, \text{sq ft}

Step 2: Area of the Ceiling

The area of the ceiling is: Ceiling Area=L×B=13×12=156sq ft\text{Ceiling Area} = L \times B = 13 \times 12 = 156 \, \text{sq ft}

Step 3: Total Area of Windows and Door

The area of the two windows and one door is: Window Area=2×(3×4)=2×12=24sq ft\text{Window Area} = 2 \times (3 \times 4) = 2 \times 12 = 24 \, \text{sq ft} Door Area=3×6=18sq ft\text{Door Area} = 3 \times 6 = 18 \, \text{sq ft} Total Area of Door and Windows=24+18=42sq ft\text{Total Area of Door and Windows} = 24 + 18 = 42 \, \text{sq ft}

Step 4: Paintable Area

The paintable area is the total area of the walls and ceiling minus the area of the door and windows: Paintable Area=(Wall Area+Ceiling Area)Total Area of Door and Windows\text{Paintable Area} = (\text{Wall Area} + \text{Ceiling Area}) - \text{Total Area of Door and Windows} Paintable Area=(500+156)42=65642=614sq ft\text{Paintable Area} = (500 + 156) - 42 = 656 - 42 = 614 \, \text{sq ft}

Step 5: Cost of Painting

The cost of painting the room is: Cost=Paintable Area×Cost per sq ft\text{Cost} = \text{Paintable Area} \times \text{Cost per sq ft} Cost=614×40=24,560Rs.\text{Cost} = 614 \times 40 = 24,560 \, \text{Rs.}

Thus, the cost of painting the walls and ceiling is Rs. 24,560.

Part (b):

We are asked to find the increase in cost if the rate per square foot is increased by 25%.

Step 6: New Cost per Square Foot

If the cost per square foot is increased by 25%, the new cost per square foot will be: New Cost per sq ft=40+0.25×40=40+10=50Rs.\text{New Cost per sq ft} = 40 + 0.25 \times 40 = 40 + 10 = 50 \, \text{Rs.}

Step 7: New Total Cost

The new total cost will be: New Cost=614×50=30,700Rs.\text{New Cost} = 614 \times 50 = 30,700 \, \text{Rs.}

Step 8: Increase in Cost

The increase in cost is: Increase=New CostOld Cost=30,70024,560=6,140Rs.\text{Increase} = \text{New Cost} - \text{Old Cost} = 30,700 - 24,560 = 6,140 \, \text{Rs.}

Thus, the total cost will increase by Rs. 6,140 if the rate increases by 25%.


Would you like more details on any part of this solution?

Related Questions:

  1. How is the total surface area of a cuboid calculated?
  2. How would the cost change if the room had additional windows or doors?
  3. What is the formula for calculating the area of a rectangular surface?
  4. How does a percentage increase in cost affect the total expense?
  5. What would the total cost be if the rate increased by 50% instead of 25%?

Tip: When calculating costs involving increases or decreases, always apply the percentage change directly to the original rate to avoid confusion.

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Math Problem Analysis

Mathematical Concepts

Surface Area
Cost Calculation
Percentage Increase

Formulas

Total surface area of four walls = 2 * (Length * Height) + 2 * (Breadth * Height)
Ceiling Area = Length * Breadth
Cost of painting = Paintable Area * Cost per square foot
New Cost per sq ft = Original Cost + 0.25 * Original Cost
Increase in Cost = New Total Cost - Old Total Cost

Theorems

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Suitable Grade Level

Grades 8-10