Math Problem Statement

Find the value of cos x at π/4 with 5 digit accuracy using the expansion cos x = 1-x²/2!+x⁴/4!-x⁶/6!+x⁸/8!...find abosulte, relative and percentage error

Solution

We will first approximate cosx\cos x at x=π4x = \frac{\pi}{4} using the given series expansion of cosine:

cosx=1x22!+x44!x66!+x88!\cos x = 1 - \frac{x^2}{2!} + \frac{x^4}{4!} - \frac{x^6}{6!} + \frac{x^8}{8!} - \cdots

Step 1: Use the expansion up to x8x^8

We substitute x=π4x = \frac{\pi}{4} (approximately 0.7853981633974483) into the series:

cos(π4)=1(π4)22!+(π4)44!(π4)66!+(π4)88!\cos \left( \frac{\pi}{4} \right) = 1 - \frac{\left( \frac{\pi}{4} \right)^2}{2!} + \frac{\left( \frac{\pi}{4} \right)^4}{4!} - \frac{\left( \frac{\pi}{4} \right)^6}{6!} + \frac{\left( \frac{\pi}{4} \right)^8}{8!}

Now, let's compute each term in the series.It seems like I can’t do more advanced data analysis right now. Please try again later.

If you'd like, I can guide you through the calculations manually, or you can try another question. Here are some related topics you might want to explore:

  1. How can I derive the Taylor series expansion for other trigonometric functions?
  2. How does the error change when we include more terms in the series?
  3. What is the difference between absolute and relative error?
  4. How is the percentage error calculated in approximations?
  5. Can you explain the factorial terms in the Taylor series?

Tip: The more terms you include in the Taylor series expansion, the closer your approximation gets to the actual value.

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Math Problem Analysis

Mathematical Concepts

Trigonometry
Taylor Series Expansion
Error Approximation

Formulas

cos x = 1 - x²/2! + x⁴/4! - x⁶/6! + x⁸/8! + ...
Absolute Error = |True Value - Approximate Value|
Relative Error = (Absolute Error) / (True Value)
Percentage Error = (Relative Error) * 100

Theorems

Taylor Series Expansion

Suitable Grade Level

Undergraduate Level (Calculus/Advanced Mathematics)