Math Problem Statement

Compute the correlation coefficient between x and y using the given data points: x = [6, 3, 1, 4, 5] and y = [5, 3, 2, 7, 1]. Round the answer to three decimal places.

Solution

To compute the correlation coefficient rr between the two variables xx and yy, we can use the formula:

r=n(xy)xy(nx2(x)2)(ny2(y)2)r = \frac{n \sum(xy) - \sum x \sum y}{\sqrt{\left(n \sum x^2 - (\sum x)^2\right) \left(n \sum y^2 - (\sum y)^2\right)}}

where:

  • nn is the number of data points,
  • x\sum x and y\sum y are the sums of the xx- and yy-values,
  • (xy)\sum(xy) is the sum of the products of corresponding xx- and yy-values,
  • x2\sum x^2 and y2\sum y^2 are the sums of squares of the xx- and yy-values.

Given data

The values provided are:

  • x:6,3,1,4,5x: 6, 3, 1, 4, 5
  • y:5,3,2,7,1y: 5, 3, 2, 7, 1

Step-by-Step Calculation

  1. Calculate x\sum x, y\sum y, x2\sum x^2, y2\sum y^2, and (xy)\sum(xy):

    • x=6+3+1+4+5=19\sum x = 6 + 3 + 1 + 4 + 5 = 19
    • y=5+3+2+7+1=18\sum y = 5 + 3 + 2 + 7 + 1 = 18
    • x2=62+32+12+42+52=36+9+1+16+25=87\sum x^2 = 6^2 + 3^2 + 1^2 + 4^2 + 5^2 = 36 + 9 + 1 + 16 + 25 = 87
    • y2=52+32+22+72+12=25+9+4+49+1=88\sum y^2 = 5^2 + 3^2 + 2^2 + 7^2 + 1^2 = 25 + 9 + 4 + 49 + 1 = 88
    • (xy)=(65)+(33)+(12)+(47)+(51)=30+9+2+28+5=74\sum(xy) = (6 \cdot 5) + (3 \cdot 3) + (1 \cdot 2) + (4 \cdot 7) + (5 \cdot 1) = 30 + 9 + 2 + 28 + 5 = 74
  2. Plug values into the formula:

    r=574(1918)(587192)(588182)r = \frac{5 \cdot 74 - (19 \cdot 18)}{\sqrt{(5 \cdot 87 - 19^2) (5 \cdot 88 - 18^2)}}

  3. Simplify each part:

    • 574=3705 \cdot 74 = 370
    • 1918=34219 \cdot 18 = 342
    • 587=4355 \cdot 87 = 435
    • 192=36119^2 = 361
    • 588=4405 \cdot 88 = 440
    • 182=32418^2 = 324

    Substitute these into the equation:

    r=370342(435361)(440324)r = \frac{370 - 342}{\sqrt{(435 - 361)(440 - 324)}}

  4. Further simplification:

    • 370342=28370 - 342 = 28
    • 435361=74435 - 361 = 74
    • 440324=116440 - 324 = 116

    So,

    r=2874116r = \frac{28}{\sqrt{74 \cdot 116}}

  5. Calculate the denominator:

    • 74116=858474 \cdot 116 = 8584
    • 858492.65\sqrt{8584} \approx 92.65

    Finally,

    r2892.650.302r \approx \frac{28}{92.65} \approx 0.302

Answer

The correlation coefficient, rounded to three decimal places, is:

0.302\boxed{0.302}

Would you like a further breakdown or have any questions about this solution?


Related Questions:

  1. How is the correlation coefficient interpreted in terms of strength and direction?
  2. What is the difference between a positive and negative correlation?
  3. How would the correlation coefficient change if one of the yy-values was altered?
  4. What does a correlation coefficient of zero signify?
  5. How can you compute the correlation coefficient using a calculator or software?

Tip:

When calculating correlation by hand, double-check the sums for each component (like x\sum x and y\sum y) to ensure accuracy, as errors in these values propagate through the entire calculation.

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Math Problem Analysis

Mathematical Concepts

Statistics
Correlation Coefficient
Data Analysis

Formulas

Correlation coefficient formula: r = (n Σ(xy) - Σx Σy) / sqrt((n Σ(x^2) - (Σx)^2)(n Σ(y^2) - (Σy)^2))

Theorems

Properties of correlation coefficients

Suitable Grade Level

Grades 10-12