Math Problem Statement

Write (√2)sinA-(√2)cosA in the form rsin(A-x)

Solution

We are asked to write 2sinA2cosA\sqrt{2} \sin A - \sqrt{2} \cos A in the form rsin(Ax)r \sin(A - x). This is a standard form conversion where we combine the sine and cosine terms into a single sine function.

Step 1: Recall the formula for rsin(Ax)r \sin(A - x)

The general form rsin(Ax)r \sin(A - x) can be expanded using the angle subtraction identity: rsin(Ax)=r[sinAcosxcosAsinx]r \sin(A - x) = r [\sin A \cos x - \cos A \sin x] We want to match this with the expression 2sinA2cosA\sqrt{2} \sin A - \sqrt{2} \cos A.

Step 2: Identify coefficients

From the expression 2sinA2cosA\sqrt{2} \sin A - \sqrt{2} \cos A, we can see: a=2(coefficient of sinA)a = \sqrt{2} \quad \text{(coefficient of } \sin A\text{)} b=2(coefficient of cosA)b = -\sqrt{2} \quad \text{(coefficient of } \cos A\text{)}

Step 3: Compute rr

We use the formula r=a2+b2r = \sqrt{a^2 + b^2} to find the amplitude rr: r=(2)2+(2)2=2+2=4=2r = \sqrt{(\sqrt{2})^2 + (-\sqrt{2})^2} = \sqrt{2 + 2} = \sqrt{4} = 2

Step 4: Compute xx

Next, we find the phase shift xx using the relations: cosx=ar=22,sinx=br=22\cos x = \frac{a}{r} = \frac{\sqrt{2}}{2}, \quad \sin x = \frac{-b}{r} = \frac{\sqrt{2}}{2} Since both cosx\cos x and sinx\sin x are positive, xx lies in the first quadrant. Specifically, cosx=sinx=22\cos x = \sin x = \frac{\sqrt{2}}{2}, which corresponds to: x=45orx=π4 radiansx = 45^\circ \quad \text{or} \quad x = \frac{\pi}{4} \text{ radians}

Step 5: Write the final expression

Thus, the expression 2sinA2cosA\sqrt{2} \sin A - \sqrt{2} \cos A can be written in the form rsin(Ax)r \sin(A - x) as: 2sin(Aπ4)2 \sin\left(A - \frac{\pi}{4}\right)

Final Answer:

2sinA2cosA=2sin(Aπ4)\sqrt{2} \sin A - \sqrt{2} \cos A = 2 \sin\left(A - \frac{\pi}{4}\right)

Would you like further details or have any questions?

Related Questions:

  1. How can we convert rcos(Ax)r \cos(A - x) into a different trigonometric form?
  2. What is the geometric meaning of converting to the form rsin(Ax)r \sin(A - x)?
  3. How does the phase shift xx affect the graph of sin(Ax)\sin(A - x)?
  4. Can you express 3sinA+4cosA3 \sin A + 4 \cos A in the form rsin(Ax)r \sin(A - x)?
  5. How would you convert sinA+3cosA\sin A + \sqrt{3} \cos A into the form rcos(A+x)r \cos(A + x)?

Tip:

The conversion to the form rsin(Ax)r \sin(A - x) is useful in simplifying trigonometric expressions, especially in solving equations and analyzing waveforms.

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Math Problem Analysis

Mathematical Concepts

Trigonometry
Angle Addition and Subtraction Formulas
Sine and Cosine Functions

Formulas

r sin(A - x) = r [sin A cos x - cos A sin x]
r = sqrt(a^2 + b^2)
cos x = a / r
sin x = -b / r

Theorems

Angle Subtraction Identity

Suitable Grade Level

Grades 10-12