Math Problem Statement

What are the ways we can convert the sin2x\sin^2x

Solution

There are multiple ways to convert or rewrite sin2x\sin^2 x depending on the context of the problem. Below are some common transformations:

1. Using the Pythagorean Identity

From the fundamental Pythagorean identity:
sin2x+cos2x=1\sin^2 x + \cos^2 x = 1 Solving for sin2x\sin^2 x: sin2x=1cos2x\sin^2 x = 1 - \cos^2 x This form is useful when you need to express sin2x\sin^2 x in terms of cosx\cos x.


2. Using the Double-Angle Identity of Cosine

From the double-angle identity: cos2x=cos2xsin2x\cos 2x = \cos^2 x - \sin^2 x Using cos2x=1sin2x\cos^2 x = 1 - \sin^2 x, we rewrite: cos2x=12sin2x\cos 2x = 1 - 2\sin^2 x Solving for sin2x\sin^2 x: sin2x=1cos2x2\sin^2 x = \frac{1 - \cos 2x}{2} This transformation is particularly useful in integration and trigonometric simplifications.


3. Using the Half-Angle Identity

The half-angle identity provides another way to express sin2x\sin^2 x: sin2x=1cos2x2\sin^2 x = \frac{1 - \cos 2x}{2} This is the same as the previous result derived from the double-angle identity.


4. Using Power Reduction Formula

Since sin2x\sin^2 x appears in trigonometric power reduction formulas, the most common transformation is: sin2x=1cos2x2\sin^2 x = \frac{1 - \cos 2x}{2} which is useful in integrals involving even powers of sine.


5. In Terms of Exponentials (Euler's Formula)

Using Euler’s formula: sinx=eixeix2i\sin x = \frac{e^{ix} - e^{-ix}}{2i} Squaring both sides: sin2x=(eixeix2i)2\sin^2 x = \left(\frac{e^{ix} - e^{-ix}}{2i}\right)^2 Expanding: sin2x=(e2ix2+e2ix)4\sin^2 x = \frac{- (e^{2ix} - 2 + e^{-2ix})}{4} Simplifying: sin2x=1e2ixe2ix4\sin^2 x = \frac{1 - e^{2ix} - e^{-2ix}}{4} Using e2ix+e2ix=2cos2xe^{2ix} + e^{-2ix} = 2\cos 2x, we get: sin2x=1cos2x2\sin^2 x = \frac{1 - \cos 2x}{2} This again leads to the well-known power-reduction formula.


Summary of Conversions:

sin2x=1cos2x\sin^2 x = 1 - \cos^2 x sin2x=1cos2x2\sin^2 x = \frac{1 - \cos 2x}{2} sin2x=1e2ixe2ix4\sin^2 x = \frac{1 - e^{2ix} - e^{-2ix}}{4}

Would you like a step-by-step derivation for any of these?


Related Questions:

  1. How can we express cos2x\cos^2 x in different forms?
  2. What is the integral of sin2x\sin^2 x?
  3. How does the power reduction formula help in trigonometric integrals?
  4. How do we use Euler’s formula to derive trigonometric identities?
  5. What are the applications of the double-angle formulas?

Tip:

When solving trigonometric integrals, the power reduction identity is particularly useful to convert squared sine and cosine terms into forms that are easier to integrate.

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Math Problem Analysis

Mathematical Concepts

Trigonometry
Pythagorean Identities
Double-Angle Identity
Euler's Formula
Power Reduction Formula

Formulas

sin^2 x = 1 - cos^2 x
sin^2 x = (1 - cos 2x) / 2
sin^2 x = (1 - e^{2ix} - e^{-2ix}) / 4

Theorems

Pythagorean Identity
Double-Angle Identity
Power Reduction Identity
Euler's Formula

Suitable Grade Level

Grades 11-12