Math Problem Statement

Convert the complex number 8 + 6j from rectangular form to polar form.

Solution

The image contains steps for converting a complex number 8+6j8 + 6j from rectangular form to polar form.

Breakdown of Steps in the Image:

  1. Rectangular Form: z=x+iyz = x + iy Here, x=8x = 8 and y=6y = 6.

  2. Magnitude (rr): r=x2+y2r = \sqrt{x^2 + y^2} Substituting values: r=82+62=64+36=100=10r = \sqrt{8^2 + 6^2} = \sqrt{64 + 36} = \sqrt{100} = 10

  3. Argument (θ\theta): θ=tan1(yx)\theta = \tan^{-1}\left(\frac{y}{x}\right) Substituting values: θ=tan1(68)\theta = \tan^{-1}\left(\frac{6}{8}\right) Simplifying: θ=tan1(0.75)36.837\theta = \tan^{-1}(0.75) \approx 36.8^\circ \approx 37^\circ

  4. Polar Form: The polar form of zz is: z=r(cosθ+isinθ)z = r(\cos \theta + i\sin \theta) Substituting r=10r = 10 and θ=37\theta = 37^\circ: z=10(cos37+isin37)z = 10(\cos 37^\circ + i\sin 37^\circ)


Would you like further clarification on any part?

5 Related Questions:

  1. How do you convert polar form back to rectangular form?
  2. What is the significance of the magnitude and argument in polar representation?
  3. How do you compute tan1\tan^{-1} for angles in radians?
  4. How is this process different if zz lies in a different quadrant?
  5. Can you explain the relationship between polar and exponential forms of complex numbers?

Tip:

Always ensure that your calculator is set to the correct mode (degrees or radians) when finding arguments of complex numbers.

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Math Problem Analysis

Mathematical Concepts

Complex Numbers
Rectangular to Polar Conversion
Trigonometry

Formulas

r = sqrt(x^2 + y^2)
θ = tan^(-1)(y/x)
z = r(cos θ + i sin θ)

Theorems

Pythagoras' Theorem for Magnitude
Inverse Tangent Function for Angle

Suitable Grade Level

Grades 10-12