Math Problem Statement

The function f(x) = 2(x + 5)^2 can be written in standard form as f(x) = 2x^2 + kx + 50, where k represents a number. What is the value of k?

Solution

We are given the function:

f(x)=2(x+5)2f(x) = 2(x + 5)^2

We need to expand and rewrite it in standard quadratic form:

f(x)=2x2+kx+50f(x) = 2x^2 + kx + 50

Step 1: Expand (x+5)2(x+5)^2

(x+5)2=x2+10x+25(x+5)^2 = x^2 + 10x + 25

Step 2: Multiply by 2

f(x)=2(x2+10x+25)f(x) = 2(x^2 + 10x + 25)

=2x2+20x+50= 2x^2 + 20x + 50

Step 3: Compare with Standard Form

2x2+20x+502x^2 + 20x + 50

Comparing coefficients, we see that k=20k = 20.

Final Answer: 20\boxed{20}

Would you like a further breakdown of any step?

Related Questions:

  1. How do you expand a squared binomial like (x+5)2(x + 5)^2?
  2. What is the general formula for expanding (a+b)2(a + b)^2?
  3. How do you determine coefficients in a quadratic function?
  4. What is the vertex form of a quadratic equation?
  5. How do you convert vertex form to standard form?

Tip: Always check your expanded expression by distributing properly to avoid common algebraic mistakes!

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Math Problem Analysis

Mathematical Concepts

Algebra
Quadratic Equations
Expanding Binomials

Formulas

(a + b)^2 = a^2 + 2ab + b^2
Standard form of a quadratic equation: ax^2 + bx + c

Theorems

Binomial Expansion

Suitable Grade Level

Grades 8-10