To solve the formula $F = \frac{9}{5}C + 32$ for $C$ in terms of $F$, follow these steps:

1. Start with the original formula: $F = \frac{9}{5}C + 32$

2. Subtract 32 from both sides to isolate the term with $C$: $F - 32 = \frac{9}{5}C$

3. Multiply both sides of the equation by $\frac{5}{9}$ to solve for $C$: $C = \frac{5}{9}(F - 32)$

Thus, the formula for $C$ in terms of $F$ is: $C = \frac{5}{9}(F - 32)$

Would you like a more detailed explanation or examples using this formula?

Here are 5 related questions to expand on this:

1. How do you convert 100°F to Celsius using the derived formula?
2. What is the equivalent Fahrenheit temperature for 0°C?
3. How can you convert Kelvin to Fahrenheit?
4. What is the inverse operation of subtracting 32 in the formula?
5. Why is the factor $\frac{9}{5}$ used in temperature conversion?

Tip: Always remember that temperature conversions can vary between scales, so it's important to use the correct conversion factor!