Write the equation 5y-3=4x+1 in the stand form

To convert the equation \( 5y - 3 = 4x + 1 \) into standard form, we'll follow these steps:

1. **Move all terms involving variables to one side of the equation**:  
   Subtract \( 4x \) from both sides to get:  
   \[
   5y - 4x - 3 = 1
   \]

2. **Move the constant term to the other side**:  
   Add 3 to both sides to get:  
   \[
   5y - 4x = 4
   \]

3. **Arrange the equation in the form \( Ax + By = C \)**:  
   Reorder the terms as:  
   \[
   -4x + 5y = 4
   \]

To ensure the equation has positive coefficients, multiply the entire equation by -1:
\[
4x - 5y = -4
\]

So, the standard form of the equation is:
\[
4x - 5y = -4
\]

Would you like any additional details or have any questions?

### Related Questions:
1. How do you convert an equation from slope-intercept form to standard form?
2. What is the significance of the coefficients in the standard form equation?
3. How can you determine the slope from an equation in standard form?
4. What are the steps to graph an equation given in standard form?
5. How does the standard form equation relate to the equation of a line in point-slope form?

**Tip:** When converting to standard form, it's generally preferred to have the coefficient of \( x \) as a positive integer.

Learn how to convert the equation 5y - 3 = 4x + 1 into standard form 4x - 5y = -4 with detailed steps. This problem involves rearranging terms in a linear equation to the standard form Ax + By = C. Suitable for students in Grades 7-9.

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