Math Problem Statement
1Convert 11001 1 2 110011 2 to decimal: 1 ∗ 2 5 + 1 ∗ 2 4 + 0 ∗ 2 3 + 0 ∗ 2 2 + 1 ∗ 2 1 + 1 ∗ 2 0
51 1∗2 5 +1∗2 4 +0∗2 3 +0∗2 2 +1∗2 1 +1∗2 0 =51 2Convert 11001 1 2 110011 2 to octal: 11001 1 2
6 3 8 110011 2 =63 8
3Convert 34 5 10 345 10 to binary: 34 5 10
10101100 1 2 345 10 =101011001 2
4Convert 34 5 10 345 10 to hexadecimal: 34 5 10
15 9 16 345 10 =159 16
5Convert 76 7 8 767 8 to decimal: 7 ∗ 8 2 + 6 ∗ 8 1 + 7 ∗ 8 0
511 7∗8 2 +6∗8 1 +7∗8 0 =511 6Convert 76 7 8 767 8 to binary: 76 7 8
10000011 1 2 767 8 =100000111 2
7Convert 987 7 16 9877 16 to decimal: 9 ∗ 1 6 3 + 8 ∗ 1 6 2 + 7 ∗ 1 6 1 + 7 ∗ 1 6 0
38935 9∗16 3 +8∗16 2 +7∗16 1 +7∗16 0 =38935 8Convert 987 7 16 9877 16 to octal: 987 7 16
11044 7 8 9877 16 =110447 8
Solution
Let's break down and solve each problem:
1. Convert to decimal:
So, .
2. Convert to octal:
First, group the binary number in sets of three from right to left: Convert each group to octal: So, .
3. Convert to binary:
Let's divide 345 by 2 repeatedly and note the remainders: So, reading the remainders from bottom to top, .
4. Convert to hexadecimal:
Let's divide 345 by 16: So, reading from bottom to top, .
5. Convert to decimal:
So, .
6. Convert to binary:
First, convert each octal digit to its binary equivalent: So, .
7. Convert to decimal:
So, .
8. Convert to octal:
First, convert to binary: So, .
Next, group the binary number into sets of three from right to left and convert to octal: So, .
Would you like further explanations or details on any of these conversions?
Here are 5 related questions for further practice:
- Convert to hexadecimal.
- Convert to octal.
- Convert to binary.
- Convert to binary.
- Convert to binary.
Tip: Always double-check each step in number base conversions, especially when dealing with different number systems, to avoid mistakes.
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Math Problem Analysis
Mathematical Concepts
Number Base Conversion
Binary System
Octal System
Decimal System
Hexadecimal System
Formulas
Binary to Decimal: Sum of (binary digit × 2^position)
Decimal to Binary: Repeated division by 2, reading remainders
Decimal to Hexadecimal: Repeated division by 16, reading remainders
Octal to Decimal: Sum of (octal digit × 8^position)
Hexadecimal to Decimal: Sum of (hex digit × 16^position)
Theorems
-
Suitable Grade Level
Grades 9-12
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