Math Problem Statement

Convert the binary number 1001001 to octal and hexadecimal respectively. Show your work.

Solution

To convert the binary number 10010011001001 to both octal and hexadecimal, let me show the work step by step:


Conversion to Octal

  1. Group the binary digits into sets of three starting from the right (add leading zeros if necessary): 001001001001 \, 001 \, 001

  2. Convert each group to its decimal (octal) equivalent:

    • 001001 = 11 (decimal)
    • 001001 = 11 (decimal)
    • 001001 = 11 (decimal)
  3. Combine the results: 10010012=11181001001_2 = 111_8


Conversion to Hexadecimal

  1. Group the binary digits into sets of four starting from the right (add leading zeros if necessary): 000100100010001 \, 0010 \, 001 Add a leading zero to complete the last group: 0001001000010001 \, 0010 \, 0001

  2. Convert each group to its decimal (hexadecimal) equivalent:

    • 00010001 = 11 (hexadecimal)
    • 00100010 = 22 (hexadecimal)
    • 00010001 = 11 (hexadecimal)
  3. Combine the results: 10010012=49161001001_2 = 49_{16}


Final Answer:

  • Octal: 1118111_8
  • Hexadecimal: 491649_{16}

Would you like further clarification or details on any step?


Related Questions:

  1. How can binary numbers be directly converted to decimal?
  2. What is the difference between octal and hexadecimal systems in terms of digit grouping?
  3. Can we convert 10010011001001 directly to decimal and back to octal/hexadecimal?
  4. What are some practical applications of octal and hexadecimal conversions?
  5. Why is binary grouping essential when converting to octal or hexadecimal?

Tip:

Always ensure to group binary digits correctly to avoid errors in conversions!

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Math Problem Analysis

Mathematical Concepts

Binary Numbers
Octal System
Hexadecimal System
Number Base Conversions

Formulas

Binary to Octal Conversion: Group binary digits into groups of 3 (from right to left) and convert each group to its octal equivalent.
Binary to Hexadecimal Conversion: Group binary digits into groups of 4 (from right to left) and convert each group to its hexadecimal equivalent.

Theorems

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Suitable Grade Level

Grades 8-10