The image contains a math problem asking to convert a temperature from degrees Celsius to degrees Fahrenheit using the given formula:

$F = \left(\frac{9}{5} \times C\right) + 32$

where $C$ is the temperature in degrees Celsius, and $F$ is the temperature in degrees Fahrenheit.

For the specific question:

$80^\circ C = ?^\circ F$

Substitute $C = 80$ into the formula:

$F = \left(\frac{9}{5} \times 80\right) + 32$

First, calculate $\frac{9}{5} \times 80$:

$\frac{9}{5} \times 80 = 144$

Now, add 32 to the result:

$F = 144 + 32 = 176^\circ F$

So, $80^\circ C = 176^\circ F$.

Would you like more details or have any questions?

Here are some related questions:

1. How would you convert $100^\circ C$ to Fahrenheit?
2. What is the reverse formula to convert Fahrenheit to Celsius?
3. Why does the conversion formula include adding 32?
4. What are some common temperatures in both Celsius and Fahrenheit?
5. How would you calculate for negative Celsius values, like $-40^\circ C$?

Tip: Always ensure you correctly handle the order of operations in formulas to avoid miscalculations.