To express the signal level in dBmV (decibels relative to one millivolt), we use the formula:

$\text{dBmV} = 20 \times \log_{10}\left(\frac{V}{1 \text{mV}}\right)$

Where:

• $V$ is the voltage in millivolts (mV).

Given that the signal is $4700 \, \mu V$, we first convert this to millivolts: $4700 \, \mu V = 4.7 \, mV$

Now, substitute $V = 4.7 \, \text{mV}$ into the formula:

$\text{dBmV} = 20 \times \log_{10}(4.7)$

Let me calculate that for you.The signal level of 4700 microvolts is approximately 13.44 dBmV.

Would you like further details or have any questions about the calculation?

Here are five related questions to deepen understanding:

1. What is the difference between dBmV and dBuV?
2. How do you convert from dBmV to dBuV?
3. What is the significance of the 75-ohm impedance in this context?
4. How would the result change if the signal level was given in milliwatts instead of microvolts?
5. How is this formula derived from basic signal theory?

Tip: Decibels are logarithmic, so small changes in signal strength can represent large differences in the actual power or voltage.