To convert \( 120 \, \text{L·kPa} \) into joules (J), we use the fact that:

\[
1 \, \text{L·kPa} = 1 \, \text{J}
\]

Thus:

\[
120 \, \text{L·kPa} = 120 \, \text{J}
\]

So, \( 120 \, \text{L·kPa} = 120 \, \text{J} \).

Would you like more details on the conversion process or any related concepts?

Here are 5 related questions to explore:

1. How do you convert between different units of pressure and volume in other systems, such as psi or atm?
2. What are some practical applications of using L·kPa in physics and engineering?
3. How does the ideal gas law relate to the use of pressure-volume work in joules?
4. Can you explain the difference between work in thermodynamics and mechanical work?
5. How is energy conservation applied in a system involving gases?

**Tip:** When working with gas laws, always ensure units are consistent across pressure, volume, and temperature for accurate results.

Learn how to convert 120 L·kPa into Joules using the simple conversion factor of 1 L·kPa = 1 J. This problem explains key thermodynamic principles related to pressure-volume work and is ideal for students in Grades 9-12 studying physics and chemistry.

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