Math Problem Statement
Solution
The given integral is:
We are asked to determine whether this integral is convergent or divergent. If it converges, we are to evaluate it.
Step 1: Check for convergence
We need to check the behavior of the integrand at both bounds: and .
Behavior at :
For small values of , let's approximate the function . As :
- is very small compared to 2, so .
- Thus, near , the integrand behaves like .
This means the integrand behaves like as . The integral of near 0 converges because , which tends to 0 as .
So, the integrand does not cause divergence at .
Behavior as :
Now, for large values of , we analyze the asymptotic behavior of the integrand. As :
- becomes negligible compared to , so .
- Thus, for large , the integrand behaves like .
The integral of as is divergent, since .
Step 2: Conclusion
Since the integrand behaves like as , the integral diverges at the upper bound.
Thus, the given integral diverges.
Let me know if you would like more details on the analysis, or have any further questions!
Here are some related questions to explore:
- What is the general criterion for testing the convergence of improper integrals?
- How can we use comparison tests to determine the convergence of integrals?
- What are the differences between improper integrals of the first and second kind?
- Can the integral be evaluated numerically even if it diverges analytically?
- What are some typical integrands that lead to divergent integrals?
Tip: When analyzing improper integrals, focus on the behavior of the integrand at the boundaries (limits) of integration, especially at infinity or near singularities.
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Math Problem Analysis
Mathematical Concepts
Improper Integrals
Asymptotic Behavior
Convergence Tests
Formulas
Integral of \( x^2 \) and \( x^{1/2} \)
Asymptotic approximation for large x
Theorems
Test for divergence using behavior at infinity
Suitable Grade Level
Undergraduate level (Calculus II or III)
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