Math Problem Statement
answer 28 and 30
Solution
Let's work through the contour maps for the functions in exercises 28 and 30.
Problem 28:
To understand the contour map of this function, we need to set where is a constant, which will define the level curves.
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Starting with the equation: By exponentiating both sides, we get: This represents an ellipse, where the constant determines the size of the ellipse. For different values of , we will get ellipses of different sizes.
The general form of these ellipses is: These are elongated in the -direction since the coefficient of is multiplied by 4. The contour map will show a series of nested ellipses, centered at the origin.
Problem 30:
For this function, we set , where is a constant:
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Setting the function equal to , we have: Solving for , we get: This equation represents a set of cosine curves for different values of . For each constant , we get a cosine curve along the -axis, scaled vertically by the value of .
The contour map will therefore consist of a series of cosine curves, where determines the amplitude of the curve.
Summary of Contour Maps:
- Problem 28: The contours are ellipses centered at the origin, with varying sizes.
- Problem 30: The contours are cosine curves with different amplitudes based on the constant .
Would you like more details or visual explanations for these functions?
Here are 5 questions related to these problems:
- What is the effect of increasing on the contour map of ?
- How do the ellipses in problem 28 change when and values vary?
- What role does the secant function play in shaping the contour map of ?
- How would the contour map change if the function in problem 30 was instead?
- What does the cosine behavior imply about the periodicity in the contour map of problem 30?
Tip: For functions involving trigonometric terms like , pay attention to the periodic nature of the curves, as they often introduce repeating structures in contour maps.
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Math Problem Analysis
Mathematical Concepts
Calculus
Contour Maps
Logarithmic Functions
Trigonometric Functions
Formulas
f(x, y) = \ln(x^2 + 4y^2)
f(x, y) = y \sec x
Contour equation: f(x, y) = c
Ellipse equation: x^2 + 4y^2 = e^c
Cosine equation: y = c \cos x
Theorems
Properties of Contour Maps
Properties of Ellipses
Properties of Trigonometric Functions
Suitable Grade Level
Undergraduate (Calculus I/II)
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