Math Problem Statement

A Better Investment You open an account by investing $250 with a financial institution that advertises an APR of 5.75%, with continuous compounding. a. Find an exponential formula for the balance in your account as a function of time. In your answer, give both the standard form and the alternative form for an exponential function. b. What account balance would you expect 5 years after your initial investment? Answer this question using both of the forms you found in part a. Which do you think gives a more accurate answer? Why?

Solution

Let’s break this problem into its parts:


Part (a): Exponential Formula for the Balance

The general formula for continuous compounding is:

A(t)=PertA(t) = P e^{rt}

Where:

  • A(t)A(t): The account balance at time tt,
  • P=250P = 250: The initial investment,
  • r=0.0575r = 0.0575: The annual percentage rate (APR) as a decimal,
  • tt: Time in years.

Substitute the values into the formula:

A(t)=250e0.0575tA(t) = 250 e^{0.0575t}


Alternative Form

An exponential function can also be written in the standard base-2 form:

A(t)=A0(b)tA(t) = A_0 \cdot (b)^{t}

Here:

  • b=er=e0.05751.0592b = e^r = e^{0.0575} \approx 1.0592,
  • A0=250A_0 = 250.

Thus:

A(t)=250(1.0592)tA(t) = 250 \cdot (1.0592)^t

Summary of the Two Forms:

  1. Standard (Base ee) Form: A(t)=250e0.0575tA(t) = 250 e^{0.0575t}
  2. Alternative (Base 10) Form: A(t)=250(1.0592)tA(t) = 250 \cdot (1.0592)^t

Part (b): Account Balance After 5 Years

We will calculate the account balance using both forms:

  1. Using Standard Form: A(5)=250e0.05755=250e0.28752501.333333.25A(5) = 250 e^{0.0575 \cdot 5} = 250 e^{0.2875} \approx 250 \cdot 1.333 \approx 333.25

  2. Using Alternative Form: A(5)=250(1.0592)52501.333333.25A(5) = 250 \cdot (1.0592)^5 \approx 250 \cdot 1.333 \approx 333.25


Which is More Accurate?

Both forms yield the same result because they are mathematically equivalent. However:

  • The standard form A(t)=250e0.0575tA(t) = 250 e^{0.0575t} is often considered more precise since it uses the natural exponential base ee directly, which avoids rounding errors inherent in using approximations for e0.0575e^{0.0575} like 1.05921.0592.

Final Answers

(a) The formulas are:

  • Standard Form: A(t)=250e0.0575tA(t) = 250 e^{0.0575t}
  • Alternative Form: A(t)=250(1.0592)tA(t) = 250 \cdot (1.0592)^t

(b) Account Balance After 5 Years:

  • Using Standard Form: $333.25\$333.25
  • Using Alternative Form: $333.25\$333.25

Both forms provide the same result, but the standard form is generally more accurate for theoretical purposes.


Do you have any questions or need additional explanations?
Here are some follow-up questions to explore this concept further:

  1. How would the formula change if the APR were compounded annually instead of continuously?
  2. What happens to the account balance if the APR increases to 6%?
  3. How long would it take for the balance to double with continuous compounding?
  4. Can you rewrite the exponential function using logarithms?
  5. What is the significance of the constant ee in financial calculations?

Tip: Continuous compounding maximizes the growth of your investment because it assumes the interest is being added infinitely often over time!

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Math Problem Analysis

Mathematical Concepts

Exponential Growth
Continuous Compounding
Interest Rates

Formulas

A(t) = P e^(rt)
A(t) = A0 * b^t, where b = e^r

Theorems

Exponential Function Properties

Suitable Grade Level

Grades 10-12 or College Level