Math Problem Statement
A person places $3560 in an investment account earning an annual rate of 6.3%, compounded continuously. Using the formula V, equals, P, e, start superscript, r, t, end superscriptV=Pe rt , where V is the value of the account in t years, P is the principal initially invested, e is the base of a natural logarithm, and r is the rate of interest, determine the amount of money, to the nearest cent, in the account after 14 years.
Solution
To find the amount of money in the account after 14 years, we'll use the continuous compounding formula:
where:
- = the future value of the investment after time .
- = the principal amount initially invested ($3560).
- = the annual interest rate (6.3%, or 0.063 as a decimal).
- = the time in years (14 years).
- = the base of the natural logarithm (approximately 2.71828).
Substituting the given values into the formula:
Let's calculate this value.The amount of money in the account after 14 years, compounded continuously at an annual rate of 6.3%, is approximately $8599.99.
Would you like more details on the calculation or have any other questions? Here are some related questions:
- How would the amount change if the interest rate were different?
- What would be the value if compounded annually instead of continuously?
- How does continuous compounding differ from other compounding methods?
- What if the investment period was 20 years instead of 14?
- How would a different initial principal affect the final amount?
Tip: Continuous compounding generally yields more than other compounding methods, as it accumulates interest constantly rather than at fixed intervals.
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Math Problem Analysis
Mathematical Concepts
Exponential Growth
Continuous Compounding
Natural Logarithm
Formulas
Continuous Compounding Formula: V = Pe^(rt)
Theorems
Exponential Growth Theorem
Suitable Grade Level
Grades 10-12
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