Math Problem Statement

construct the perpendicular bisector of a line segment.

Solution

To construct the perpendicular bisector of a line segment, follow these steps:

  1. Draw the Line Segment: Start by drawing the line segment ABAB that you want to bisect.

  2. Set Compass Width: Place the compass point on one endpoint of the line segment, AA. Open the compass to slightly more than half the length of ABAB.

  3. Draw Arcs from Endpoint AA: With the compass set, draw an arc above and another arc below the line segment, keeping the compass point at AA.

  4. Draw Arcs from Endpoint BB: Without changing the compass width, place the compass point on the other endpoint BB. Draw another arc above and below the line segment to intersect the first set of arcs.

  5. Mark Intersection Points: The two pairs of arcs should intersect above and below the line segment. Mark these intersection points as PP and QQ.

  6. Draw the Perpendicular Bisector: Use a straightedge to draw a line through points PP and QQ. This line is the perpendicular bisector of segment ABAB. It bisects ABAB at a 90° angle and passes through the midpoint of ABAB.

Now you have constructed the perpendicular bisector of ABAB!

Would you like a diagram or further clarification on any of these steps?


Here are some follow-up questions to deepen your understanding:

  1. How can you verify that the line is perpendicular to the segment?
  2. Why does the perpendicular bisector pass through the midpoint?
  3. Can you use this method for any line segment, regardless of its length?
  4. What is the significance of a perpendicular bisector in geometry?
  5. How would you find the coordinates of the midpoint if AA and BB have given coordinates?

Tip: When constructing arcs with a compass, ensure it is slightly more than half the segment to guarantee intersection points above and below the line.

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Math Problem Analysis

Mathematical Concepts

Geometry
Perpendicular Bisector
Compass and Straightedge Construction

Formulas

Midpoint formula

Theorems

Perpendicular Bisector Theorem

Suitable Grade Level

Grades 6-8