Math Problem Statement

  1. Construct a histogram from the following frequency distribution on temperatures. (fill in the limits, too). Class Limits Class boundaries Frequency 28.5–31.5 1 31.5–34.5 3 34.5–37.5 6 37.5–40.5 10 40.5–43.5 8 43.5–46.5 7

Solution

To construct a histogram from the given frequency distribution, we'll start by defining the class limits, class boundaries, and frequencies. The class boundaries are used to avoid gaps between bars in the histogram, and they are typically adjusted slightly from the class limits.

Here's the data as presented, with boundaries:

Class LimitsClass BoundariesFrequency
28.5–31.528.5–31.51
31.5–34.531.5–34.53
34.5–37.534.5–37.56
37.5–40.537.5–40.510
40.5–43.540.5–43.58
43.5–46.543.5–46.57

Steps to Construct the Histogram:

  1. X-axis: Use the class boundaries (e.g., 28.5–31.5, 31.5–34.5, etc.) for the x-axis.
  2. Y-axis: Use the frequencies (1, 3, 6, 10, 8, 7) for the y-axis.
  3. Bars: Draw rectangular bars for each class boundary interval. The height of each bar corresponds to the frequency for that interval.

Here's a quick guide to help visualize:

  • The first bar corresponds to the interval 28.5–31.5 with a height of 1.
  • The second bar is for 31.5–34.5 with a height of 3.
  • The process continues for all intervals, with the highest bar at the interval 37.5–40.5 (frequency = 10).

Would you like me to create a visual histogram for you?


Related Questions:

  1. How do we calculate class width in a frequency distribution?
  2. What is the difference between class limits and class boundaries?
  3. How can we interpret the shape of a histogram?
  4. How does the choice of bin size affect the histogram?
  5. Can a histogram be used for categorical data?

Tip: When constructing histograms, always ensure there are no gaps between bars by using class boundaries instead of class limits.

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Math Problem Analysis

Mathematical Concepts

Statistics
Histogram
Frequency Distribution

Formulas

Class boundaries = Adjusted class limits
Frequency = Count of occurrences in each class interval

Theorems

N/A

Suitable Grade Level

Grades 6-8