Math Problem Statement

A polynomial of degree 8, P⁡(x) has leading coefficient 1, and has roots of multiplicity 1 at x=0, multiplicity 3 at x=-4, and multiplicity 4 at x=-2.

Solution

Given the conditions for the polynomial P(x)P(x):

  • The polynomial is of degree 8.
  • The leading coefficient is 1.
  • There is a root of multiplicity 1 at x=0x = 0.
  • There is a root of multiplicity 3 at x=4x = -4.
  • There is a root of multiplicity 4 at x=2x = -2.

We can express P(x)P(x) in its factored form as follows:

P(x)=a(x0)1(x+4)3(x+2)4P(x) = a(x - 0)^1(x + 4)^3(x + 2)^4

Given that the leading coefficient is 1, the constant a=1a = 1. Thus, the polynomial simplifies to:

P(x)=x(x+4)3(x+2)4P(x) = x(x + 4)^3(x + 2)^4

This is the polynomial P(x)P(x) that satisfies all the given conditions.

Would you like more details or have any questions?

Here are some related questions:

  1. How can the degree of a polynomial be determined by its roots?
  2. What is the significance of the leading coefficient in a polynomial?
  3. How do you find the multiplicity of a root in a polynomial?
  4. How would the polynomial change if the leading coefficient was different?
  5. Can you graph the polynomial to verify its roots and multiplicities?

Tip: Always check that the sum of the multiplicities of the roots matches the degree of the polynomial to ensure accuracy.

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Math Problem Analysis

Mathematical Concepts

Polynomials
Roots and Multiplicities

Formulas

Polynomial factoring

Theorems

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Suitable Grade Level

High School