Math Problem Statement
A polynomial of degree 8, P(x) has leading coefficient 1, and has roots of multiplicity 1 at x=0, multiplicity 3 at x=-4, and multiplicity 4 at x=-2.
Solution
Given the conditions for the polynomial :
- The polynomial is of degree 8.
- The leading coefficient is 1.
- There is a root of multiplicity 1 at .
- There is a root of multiplicity 3 at .
- There is a root of multiplicity 4 at .
We can express in its factored form as follows:
Given that the leading coefficient is 1, the constant . Thus, the polynomial simplifies to:
This is the polynomial that satisfies all the given conditions.
Would you like more details or have any questions?
Here are some related questions:
- How can the degree of a polynomial be determined by its roots?
- What is the significance of the leading coefficient in a polynomial?
- How do you find the multiplicity of a root in a polynomial?
- How would the polynomial change if the leading coefficient was different?
- Can you graph the polynomial to verify its roots and multiplicities?
Tip: Always check that the sum of the multiplicities of the roots matches the degree of the polynomial to ensure accuracy.
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Math Problem Analysis
Mathematical Concepts
Polynomials
Roots and Multiplicities
Formulas
Polynomial factoring
Theorems
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Suitable Grade Level
High School
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