Math Problem Statement

Consider the following constrained nonlinear programming prob- lem. min f0(x1, x2) s.t. 2x1 + x2 ≥ 1, x1 + 3x2 ≥ 1, x1 ≥ 0, x2 ≥ 0. Sketch the feasible region S.

Solution

To analyze and sketch the feasible region SS for the given constrained nonlinear programming problem, we start by interpreting the constraints:

Problem:

minf0(x1,x2)\min f_0(x_1, x_2) subject to: 2x1+x21(C1)2x_1 + x_2 \geq 1 \quad (C_1) x1+3x21(C2)x_1 + 3x_2 \geq 1 \quad (C_2) x10(C3)x_1 \geq 0 \quad (C_3) x20(C4)x_2 \geq 0 \quad (C_4)

Step 1: Rewrite the constraints

We can rewrite the inequalities to better understand the boundary lines:

  1. 2x1+x2=12x_1 + x_2 = 1 is the boundary line for C1C_1.
  2. x1+3x2=1x_1 + 3x_2 = 1 is the boundary line for C2C_2.
  3. x10x_1 \geq 0 restricts x1x_1 to the non-negative region (right half-plane).
  4. x20x_2 \geq 0 restricts x2x_2 to the non-negative region (upper half-plane).

Step 2: Find intersection points

To sketch the region, we need to find the intersection points of the boundary lines of C1C_1 and C2C_2 with each other, as well as with the axes.

Constraint C1:2x1+x2=1C_1: 2x_1 + x_2 = 1

  • If x1=0x_1 = 0, x2=1x_2 = 1. So, the point is (0,1)(0, 1).
  • If x2=0x_2 = 0, x1=12x_1 = \frac{1}{2}. So, the point is (12,0)\left( \frac{1}{2}, 0 \right).

Constraint C2:x1+3x2=1C_2: x_1 + 3x_2 = 1

  • If x1=0x_1 = 0, x2=13x_2 = \frac{1}{3}. So, the point is (0,13)\left( 0, \frac{1}{3} \right).
  • If x2=0x_2 = 0, x1=1x_1 = 1. So, the point is (1,0)(1, 0).

Step 3: Sketch the region

  • The boundary line 2x1+x2=12x_1 + x_2 = 1 passes through (12,0)\left( \frac{1}{2}, 0 \right) and (0,1)(0, 1).
  • The boundary line x1+3x2=1x_1 + 3x_2 = 1 passes through (1,0)(1, 0) and (0,13)\left( 0, \frac{1}{3} \right).

The feasible region is the area that satisfies both inequalities, which lies above both lines and in the first quadrant (since x10x_1 \geq 0 and x20x_2 \geq 0).

The feasible region can be visualized as a polygon bounded by the lines, restricted by the axes x1=0x_1 = 0 and x2=0x_2 = 0, and where both constraints hold.

I'll now summarize the key points to plot:

  1. The boundary line 2x1+x2=12x_1 + x_2 = 1 between (12,0)\left( \frac{1}{2}, 0 \right) and (0,1)(0, 1).
  2. The boundary line x1+3x2=1x_1 + 3x_2 = 1 between (1,0)(1, 0) and (0,13)\left( 0, \frac{1}{3} \right).
  3. The non-negative constraint regions: x10x_1 \geq 0 and x20x_2 \geq 0.

Would you like me to provide the plot for this feasible region? Let me know if you'd like more details or have any questions.

Here are some questions related to this topic:

  1. What is the significance of feasible regions in optimization problems?
  2. How do constraints affect the shape of the feasible region?
  3. Can the feasible region ever be unbounded? Under what conditions?
  4. What is the role of boundary lines in determining the optimal solution?
  5. How does the choice of objective function f0(x1,x2)f_0(x_1, x_2) influence the solution?

Tip: When sketching feasible regions, always find the points where constraints intersect the axes and each other to identify key boundary points.

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Math Problem Analysis

Mathematical Concepts

Constrained Optimization
Linear Inequalities
Feasible Region

Formulas

2x1 + x2 ≥ 1
x1 + 3x2 ≥ 1
x1 ≥ 0, x2 ≥ 0

Theorems

Feasible Region Theorem
Linear Inequality Solutions

Suitable Grade Level

Undergraduate (Math/Optimization courses)