Math Problem Statement

Determine the values of constants a, b, c, and d so that f(x) = ax^3 + bx^2 + cx + d has a local maximum at the point (0, 0) and a local minimum at the point (1, -4).

Solution

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extracted_textThe problem asks you to determine the values of constants aa, bb, cc, and dd such that the function f(x)=ax3+bx2+cx+df(x) = ax^3 + bx^2 + cx + d has the following properties:

  • A local maximum at the point (0,0)(0, 0)
  • A local minimum at the point (1,4)(1, -4)

To solve this, we can use the conditions for local extrema:

  1. First Derivative (Critical Points): The first derivative of f(x)f(x), f(x)f'(x), must equal zero at the points where local maxima or minima occur. This gives us the necessary condition for critical points.

  2. Second Derivative (Concavity): The second derivative of f(x)f(x), f(x)f''(x), tells us whether a point is a maximum or minimum. Specifically:

    • If f(x)>0f''(x) > 0, the function has a local minimum at that point.
    • If f(x)<0f''(x) < 0, the function has a local maximum at that point.

Let's proceed step-by-step to find the values of aa, bb, cc, and dd that satisfy these conditions.

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Math Problem Analysis

Mathematical Concepts

Calculus
Critical Points
Polynomial Functions

Formulas

f'(x) = 3ax^2 + 2bx + c (First derivative)
f''(x) = 6ax + 2b (Second derivative)

Theorems

Critical Point Theorem
Second Derivative Test

Suitable Grade Level

Grades 11-12