The product of two consecutive odd natural numbers is 323323. Find the largest number among them.

Let the two consecutive odd natural numbers be \( n \) and \( n+2 \).

### Step 1: Form the equation
The product of the two numbers is given by:
\[
n \times (n + 2) = 323323
\]

Expanding this equation:
\[
n^2 + 2n = 323323
\]

### Step 2: Rearrange the equation
Rewrite it as:
\[
n^2 + 2n - 323323 = 0
\]

### Step 3: Solve the quadratic equation
We solve the quadratic equation \( n^2 + 2n - 323323 = 0 \) using the quadratic formula:
\[
n = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}
\]
where \( a = 1 \), \( b = 2 \), and \( c = -323323 \).

### Step 4: Calculate the discriminant
The discriminant is:
\[
b

The product of two consecutive odd natural numbers is 323323. Find the largest number among them.

Solve the problem of finding two consecutive odd natural numbers whose product is 323323 with a step-by-step quadratic equation solution. Learn how to apply the quadratic formula and algebraic techniques. Suitable for high school students (Grades 9-12).

Math Problem Statement

Solution

Ask a new question for Free

By Image

Math Problem Analysis

Mathematical Concepts

Formulas

Theorems

Suitable Grade Level

Related Recommendation