Math Problem Statement

To study the daily coffee consumption habits of employees, a sample of 8 individuals were asked to report the number of cups of coffee they drank yesterday. The results are as follows: 3, 2, 4, 5, 3, 3, 4, 2. Required: 1. Find the point estimate of the mean (X̄) for the number of cups of coffee consumed per day by the employees. 2. Construct a 90% confidence interval for the population mean, assuming that the population standard deviation is 0.8 cups.

Solution

Problem Interpretation and Solution:

Question Summary:

We need to address two tasks based on a sample of coffee consumption data:

  1. Calculate the point estimate for the mean number of cups of coffee consumed per day by the employees.
  2. Construct a 90% confidence interval for the population mean, assuming a population standard deviation of 0.8 cups.

Data:

The sample data provided is:
3, 2, 4, 5, 3, 3, 4, 2

  • Sample size (n): n=8n = 8
  • Population standard deviation (σ\sigma): σ=0.8\sigma = 0.8

Solution:

  1. Point Estimate for the Mean (xˉ\bar{x}):

    The point estimate for the mean is the sample mean (xˉ\bar{x}).
    xˉ=xn\bar{x} = \frac{\sum x}{n}

    xˉ=3+2+4+5+3+3+4+28=268=3.25\bar{x} = \frac{3 + 2 + 4 + 5 + 3 + 3 + 4 + 2}{8} = \frac{26}{8} = 3.25

    Point Estimate: xˉ=3.25\bar{x} = 3.25 cups.


  1. 90% Confidence Interval for the Population Mean:

    The formula for a confidence interval is: xˉ±zσn\bar{x} \pm z \cdot \frac{\sigma}{\sqrt{n}} where:

    • zz: z-score corresponding to the confidence level (for 90%, z=1.645z = 1.645)
    • σ\sigma: population standard deviation (σ=0.8\sigma = 0.8)
    • nn: sample size (n=8n = 8)

    Step-by-step:

    • Calculate the standard error (SESE): SE=σn=0.880.2828SE = \frac{\sigma}{\sqrt{n}} = \frac{0.8}{\sqrt{8}} \approx 0.2828
    • Multiply zz and SESE to get the margin of error (ME): ME=zSE=1.6450.28280.4649ME = z \cdot SE = 1.645 \cdot 0.2828 \approx 0.4649
    • Calculate the confidence interval: Lower Limit=xˉME=3.250.46492.79\text{Lower Limit} = \bar{x} - ME = 3.25 - 0.4649 \approx 2.79 Upper Limit=xˉ+ME=3.25+0.46493.71\text{Upper Limit} = \bar{x} + ME = 3.25 + 0.4649 \approx 3.71

    90% Confidence Interval: (2.79,3.71)(2.79, 3.71)


Final Results:

  1. Point Estimate for Mean: 3.253.25 cups.
  2. 90% Confidence Interval: (2.79,3.71)(2.79, 3.71)

Would you like further clarification or detailed explanations on any step?

Here are 5 follow-up questions for exploration:

  1. How does the sample size affect the confidence interval width?
  2. Why do we use zz-values instead of tt-values in this scenario?
  3. What happens if the population standard deviation is unknown?
  4. How would increasing the confidence level to 95% impact the interval?
  5. Can we infer individual employee consumption habits from this confidence interval?

Tip: Confidence intervals provide a range of plausible values for the population mean; they don't guarantee that the population mean is within the interval!

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Math Problem Analysis

Mathematical Concepts

Statistics
Descriptive Statistics
Confidence Intervals

Formulas

Sample mean formula: X̄ = (Σx) / n
Confidence interval formula: X̄ ± z * (σ / √n)

Theorems

Central Limit Theorem

Suitable Grade Level

Undergraduate Level or AP Statistics