Math Problem Statement

A solid consists of a cone and a hemisphere which share a common base. The cone has a base radius of 35 cm. The volume of the cone is 1/5 of the volume of the hemisphere. Given that the volume of the cone is equal to 1/5 of the volume of the hemisphere, find the height of the cone.

Solution

The problem provided in the image is about a solid consisting of a cone and a hemisphere that share a common base. The radius of the base is given as 3535 cm. The volume of the cone is stated to be 15\frac{1}{5} of the volume of the hemisphere. The question asks to find:

(i) The height of the cone.

Let's solve this step-by-step:

Step 1: Find the Volume of the Hemisphere

The volume VV of a hemisphere with radius rr is given by:

Vhemisphere=23πr3V_{\text{hemisphere}} = \frac{2}{3} \pi r^3

Given r=35r = 35 cm:

Vhemisphere=23π(35)3V_{\text{hemisphere}} = \frac{2}{3} \pi (35)^3

Step 2: Set Up the Equation for the Cone's Volume

The volume of the cone VconeV_{\text{cone}} is given to be 15\frac{1}{5} of the volume of the hemisphere:

Vcone=15VhemisphereV_{\text{cone}} = \frac{1}{5} V_{\text{hemisphere}}

Substitute the value of VhemisphereV_{\text{hemisphere}}:

Vcone=15(23π(35)3)V_{\text{cone}} = \frac{1}{5} \left( \frac{2}{3} \pi (35)^3 \right)

Simplify this:

Vcone=215π(35)3V_{\text{cone}} = \frac{2}{15} \pi (35)^3

Step 3: Find the Formula for the Volume of the Cone

The volume of a cone is given by:

Vcone=13πr2hV_{\text{cone}} = \frac{1}{3} \pi r^2 h

where r=35r = 35 cm and hh is the height of the cone.

Step 4: Equate the Two Expressions for the Volume of the Cone

We have two expressions for the volume of the cone. Setting them equal to each other gives:

13π(35)2h=215π(35)3\frac{1}{3} \pi (35)^2 h = \frac{2}{15} \pi (35)^3

Step 5: Solve for the Height hh

Simplify the equation:

13π(35)2h=215π(35)3\frac{1}{3} \pi (35)^2 h = \frac{2}{15} \pi (35)^3

Cancel out π(35)2\pi (35)^2 from both sides:

13h=215×35\frac{1}{3} h = \frac{2}{15} \times 35

Multiply both sides by 3:

h=2×355=14h = \frac{2 \times 35}{5} = 14

So, the height hh of the cone is 14 cm.

Would you like more details, or do you have any other questions?

Related Questions:

  1. How do you find the volume of a sphere and how does it relate to a hemisphere?
  2. What would the total volume of the solid be (cone + hemisphere)?
  3. If the radius were doubled, how would the volume of the cone and hemisphere change?
  4. How does changing the height of the cone affect the volume ratio?
  5. Can you calculate the surface area of the solid formed by the cone and hemisphere?

Tip:

When working with volumes, always ensure you understand the geometric formulas and how they relate to the dimensions provided in the problem.

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Math Problem Analysis

Mathematical Concepts

Volume of Cone
Volume of Hemisphere
Geometry
Algebra

Formulas

Volume of hemisphere = (2/3)πr^3
Volume of cone = (1/3)πr^2h

Theorems

Relationship between cone and hemisphere volume

Suitable Grade Level

Grade 10-12