Condense the following logarithmic expressions:
1. log₃ 5 + log₃ 2
2. log₂ R + log₂ S - 2 log₂ T
3. log₅ (x² - 1) - log₅ (x - 1)
4. 4 ln (x - 3) + ½ ln x
5. ln x - ln y + ln z
Solution
Let’s condense the given logarithmic expressions step by step:
1. log35+log32
Using the logarithmic property logbA+logbB=logb(A⋅B):
log35+log32=log3(5⋅2)=log310
2. log2R+log2S−2log2T
Using the properties:
logbA+logbB=logb(A⋅B)
nlogbA=logb(An):
log2R+log2S−2log2T=log2(R⋅S)−log2(T2)
Using logbA−logbB=logb(BA):
log2R+log2S−2log2T=log2(T2R⋅S)
3. log5(x2−1)−log5(x−1)
Using logbA−logbB=logb(BA):
log5(x2−1)−log5(x−1)=log5(x−1x2−1)
Since x2−1=(x−1)(x+1), the expression simplifies to:
log5(x−1(x−1)(x+1))=log5(x+1)
4. 4ln(x−3)+21lnx
Using nlnA=ln(An):
4ln(x−3)+21lnx=ln((x−3)4)+ln(x1/2)
Using lnA+lnB=ln(A⋅B):
ln((x−3)4)+ln(x1/2)=ln((x−3)4⋅x1/2)
This simplifies to:
ln(x1/2(x−3)4)
5. lnx−lny+lnz
Using lnA−lnB=ln(BA) and lnA+lnB=ln(A⋅B):
lnx−lny+lnz=ln(yx)+lnzln(yx)+lnz=ln(yx⋅z)
This simplifies to:
ln(yx⋅z)
Final Results:
log310
log2(T2R⋅S)
log5(x+1)
ln(x1/2(x−3)4)
ln(yx⋅z)
Would you like additional steps or explanations? Here are five questions to extend your understanding:
What are the key logarithmic rules used in condensing these expressions?
How does ln relate to log, and when are they interchangeable?
Why do logarithmic properties require the same base for addition/subtraction?
What is the significance of condensing logarithmic expressions in problem-solving?
How can these properties be used to simplify complex equations?
Tip: Always check if terms can be factored or simplified before applying logarithmic properties!
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Math Problem Analysis
Mathematical Concepts
Logarithms Properties of Logarithms Simplification
Formulas
logₐ A + logₐ B = logₐ (A * B) logₐ A - logₐ B = logₐ (A / B) n logₐ A = logₐ (A^n)