To solve this, we use the formula for % (m/v) concentration:

$\text{Concentration} \, (\% \, \text{m/v}) = \frac{\text{mass of solute (g)}}{\text{volume of solution (mL)}} \times 100$

Given:

• Mass of solute ($\text{KCl}$) = 15.0 g
• Volume of solution = 600.0 mL

Substituting into the formula:

$\text{Concentration} = \frac{15.0}{600.0} \times 100$

$\text{Concentration} = 2.50\%$

Final Answer:

The concentration of the solution is 2.50%.
Correct choice: d. 2.50%.

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Related Questions:

1. What is the formula to calculate molarity for solutions?
2. How does % (m/v) concentration differ from molarity?
3. If the solution volume was halved, how would the % (m/v) concentration change?
4. What is the importance of % (m/v) concentration in real-world applications?
5. How would you prepare a solution with a specific % (m/v) concentration?

Tip: Always ensure that the units of mass and volume match the formula requirements before substituting values!