Math Problem Statement
A particle with charge q moving with velocity −→v in a magnetic field −→ B , experiences a force equal to −→ F = q−→v × −→ B (this is called the Lorentz force). Compute the force acting on a proton with charge 1.6 × 10^−19 C, moving with velocity 2 × 10^5→ k m/s in a magnetic field 0.5→ i T.
Solution
To compute the force acting on the proton, we use the formula for the Lorentz force:
Where:
- is the charge of the proton.
- is the velocity of the proton.
- is the magnetic field.
We need to compute the cross product . Since the velocity vector is along the -direction and the magnetic field is along the -direction, the cross product follows the right-hand rule.
Using the properties of the cross product:
So,
Now, calculate the force:
Thus, the force acting on the proton is:
This means the force is directed along the negative -axis.
Would you like more details or further clarifications on any step?
Here are some related questions:
- What is the right-hand rule for determining the direction of a cross product in physics?
- How does the velocity of a charged particle in a magnetic field affect the magnitude of the force?
- What is the significance of the charge sign (positive or negative) in determining the direction of the Lorentz force?
- How would the force change if the magnetic field had a different direction or magnitude?
- How does the speed of the particle affect the Lorentz force in practical scenarios like in particle accelerators?
Tip: To visualize the direction of the force using the right-hand rule, curl your fingers in the direction of and curl them toward ; your thumb will point in the direction of the force.
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Math Problem Analysis
Mathematical Concepts
Vector Calculus
Cross Product
Electromagnetism
Lorentz Force
Formulas
Lorentz Force: F = q(v × B)
Cross Product: v × B = |v||B|sin(θ)
Theorems
Right-Hand Rule
Cross Product Properties
Suitable Grade Level
Grades 10-12
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