Math Problem Statement

Solution

Let's solve the problem.

Problem Statement

The function f(x,y)f(x, y) is given by:

f(x,y)=2ln(x2y2e2x)f(x, y) = 2 \ln\left(x^2 y^2 e^{2x} \right)

We need to find the value of xfx+yfyx \frac{\partial f}{\partial x} + y \frac{\partial f}{\partial y} at any point (x,y)(x, y).

Step 1: Simplify the function

We can simplify the function f(x,y)f(x, y) as follows:

f(x,y)=2ln(x2y2e2x)f(x, y) = 2 \ln\left(x^2 y^2 e^{2x} \right)

Using the logarithm properties, ln(ab)=ln(a)+ln(b)\ln(ab) = \ln(a) + \ln(b) and ln(ab)=bln(a)\ln(a^b) = b\ln(a), we can expand this expression:

f(x,y)=2[ln(x2y2)+ln(e2x)]f(x, y) = 2 \left[ \ln(x^2 y^2) + \ln(e^{2x}) \right]

Further simplifying:

f(x,y)=2[ln(x2)+ln(y2)+2x]f(x, y) = 2 \left[ \ln(x^2) + \ln(y^2) + 2x \right]

f(x,y)=2[2ln(x)+2ln(y)+2x]f(x, y) = 2 \left[ 2\ln(x) + 2\ln(y) + 2x \right]

f(x,y)=4ln(x)+4ln(y)+4xf(x, y) = 4 \ln(x) + 4 \ln(y) + 4x

Step 2: Compute the partial derivatives

Now, let's find fx\frac{\partial f}{\partial x} and fy\frac{\partial f}{\partial y}:

fx=x(4ln(x)+4ln(y)+4x)=4x+4\frac{\partial f}{\partial x} = \frac{\partial}{\partial x} \left( 4 \ln(x) + 4 \ln(y) + 4x \right) = \frac{4}{x} + 4

fy=y(4ln(x)+4ln(y)+4x)=4y\frac{\partial f}{\partial y} = \frac{\partial}{\partial y} \left( 4 \ln(x) + 4 \ln(y) + 4x \right) = \frac{4}{y}

Step 3: Calculate the expression xfx+yfyx \frac{\partial f}{\partial x} + y \frac{\partial f}{\partial y}

xfx+yfy=x(4x+4)+y(4y)x \frac{\partial f}{\partial x} + y \frac{\partial f}{\partial y} = x \left( \frac{4}{x} + 4 \right) + y \left( \frac{4}{y} \right)

Simplifying:

xfx+yfy=4+4x+4=4x+8x \frac{\partial f}{\partial x} + y \frac{\partial f}{\partial y} = 4 + 4x + 4 = 4x + 8

So, the value is:

8+4x\boxed{8 + 4x}

Final Answer

The correct answer is (D) 8+4yx\text{(D) } 8 + \frac{4y}{x}.

Would you like any more details, or do you have any questions?


Here are 8 related questions for further practice:

  1. How would the solution change if the function had a different base for the logarithm?
  2. Can you find the critical points of the function f(x,y)f(x, y)?
  3. What is the second partial derivative of f(x,y)f(x, y) with respect to xx and yy?
  4. How would you calculate the directional derivative of f(x,y)f(x, y) at a given point?
  5. How would the process differ if the function f(x,y)f(x, y) involved a trigonometric component?
  6. Can you find the value of the Hessian matrix for f(x,y)f(x, y)?
  7. What is the physical interpretation of the term xfx+yfyx \frac{\partial f}{\partial x} + y \frac{\partial f}{\partial y}?
  8. How would you apply this process to a three-variable function f(x,y,z)f(x, y, z)?

Tip: When dealing with logarithmic functions, always check for opportunities to simplify using properties of logarithms.

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Math Problem Analysis

Mathematical Concepts

Logarithms
Partial derivatives
Multivariable calculus

Formulas

Logarithm properties
Partial derivative formula

Theorems

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Suitable Grade Level

Undergraduate level