Math Problem Statement
p:
I like math.
q:
The topic of logic is interesting.
r:
I do not miss class.
Match each compound statement to its symbolic form.
-abcdefghij (p∧q)→r
-abcdefghij p∧(q→r)
-abcdefghij (∼r→∼q)∨p
-abcdefghij (q∧r)→p
-abcdefghij r↔q∧p
-abcdefghij ∼r→∼(p∧q)
-abcdefghij ∼(p∧q)→∼r)
-abcdefghij r↔p∧q
-abcdefghij ∼r→∼p∨∼q
-abcdefghij (p↔q)∧r
I do not miss class if and only if I like math and the topic of logic is interesting.
If it isn't true that I like math and I find the topic of logic interesting, then I miss class.
If the topic of logic is interesting and I do not miss class, then I like math.
If I miss class, then I don't like math or the topic of logic is not interesting.
If I miss class, then it isn't true that I like math and the topic of logic is interesting.
I do not miss class if and only if the topic of logic is interesting and I like math.
I like math if and only if the topic of logic is interesting, and I do not miss class.
If I miss class then the topic of logic is not interesting, or I like math.
If I like math and the topic of logic is interesting, then I do not miss class.
I like math, and if the topic of logic is interesting, then I do not miss class.
Solution
Let's match the compound statements to their symbolic forms:
-
"I do not miss class if and only if I like math and the topic of logic is interesting."
- This statement implies a bi-conditional relationship between not missing class and both liking math and finding the topic of logic interesting.
- Symbolic form: r ↔ (p ∧ q)
-
"If it isn't true that I like math and I find the topic of logic interesting, then I miss class."
- This statement expresses that the negation of "I like math and find the topic of logic interesting" leads to missing class.
- Symbolic form: ∼(p ∧ q) → ∼r
-
"If the topic of logic is interesting and I do not miss class, then I like math."
- This statement implies that both the topic of logic being interesting and not missing class lead to liking math.
- Symbolic form: (q ∧ ∼r) → p
-
"If I miss class, then I don't like math or the topic of logic is not interesting."
- This is an implication stating that missing class leads to either not liking math or the topic of logic not being interesting.
- Symbolic form: ∼r → ∼p ∨ ∼q
-
"If I miss class, then it isn't true that I like math and the topic of logic is interesting."
- This statement suggests that missing class implies the negation of both liking math and the topic of logic being interesting.
- Symbolic form: ∼r → ∼(p ∧ q)
-
"I do not miss class if and only if the topic of logic is interesting and I like math."
- This is essentially the reverse of the first statement, expressing a bi-conditional between not missing class and both liking math and the topic being interesting.
- Symbolic form: ∼r ↔ (p ∧ q)
-
"I like math if and only if the topic of logic is interesting, and I do not miss class."
- This implies a bi-conditional between liking math and the topic of logic being interesting, along with not missing class.
- Symbolic form: (p ↔ q) ∧ ∼r
-
"If I miss class, then the topic of logic is not interesting, or I like math."
- This is an implication where missing class leads to either the topic of logic not being interesting or liking math.
- Symbolic form: ∼r → ∼q ∨ p
-
"If I like math and the topic of logic is interesting, then I do not miss class."
- This is an implication where both liking math and the topic of logic being interesting lead to not missing class.
- Symbolic form: (p ∧ q) → ∼r
-
"I like math, and if the topic of logic is interesting, then I do not miss class."
- This is a conjunction of liking math and an implication that the topic of logic being interesting leads to not missing class.
- Symbolic form: p ∧ (q → ∼r)
Summary of matches:
- r ↔ (p ∧ q)
- ∼(p ∧ q) → ∼r
- (q ∧ ∼r) → p
- ∼r → ∼p ∨ ∼q
- ∼r → ∼(p ∧ q)
- ∼r ↔ (p ∧ q)
- (p ↔ q) ∧ ∼r
- ∼r → ∼q ∨ p
- (p ∧ q) → ∼r
- p ∧ (q → ∼r)
Would you like further explanation on any of these?
Related questions:
- How do you prove the equivalence of two compound statements?
- What is the difference between a conjunction and a disjunction in logic?
- How can you use truth tables to verify logical statements?
- What is the significance of a bi-conditional (↔) in logic?
- Can logical implications be rewritten in terms of disjunctions?
Tip:
In logic, always break down complex compound statements into simpler components to better understand the relationships between them. This often makes it easier to translate them into symbolic form.
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Math Problem Analysis
Mathematical Concepts
Logic
Propositional Logic
Compound Statements
Symbolic Logic
Formulas
(p ∧ q) → r
p ∧ (q → r)
(∼r → ∼q) ∨ p
(q ∧ r) → p
r ↔ q ∧ p
∼r → ∼(p ∧ q)
∼(p ∧ q) → ∼r
r ↔ p ∧ q
∼r → ∼p ∨ ∼q
(p ↔ q) ∧ r
Theorems
Implication
Conjunction
Disjunction
Bi-conditional
Negation
Suitable Grade Level
Grades 11-12
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