Math Problem Statement

p:

I like math.

q:

The topic of logic is interesting.

r:

I do not miss class.

Match each compound statement to its symbolic form.

-abcdefghij (p∧q)→r

-abcdefghij p∧(q→r)

-abcdefghij (∼r→∼q)∨p

-abcdefghij (q∧r)→p

-abcdefghij r↔q∧p

-abcdefghij ∼r→∼(p∧q)

-abcdefghij ∼(p∧q)→∼r)

-abcdefghij r↔p∧q

-abcdefghij ∼r→∼p∨∼q

-abcdefghij (p↔q)∧r

I do not miss class if and only if I like math and the topic of logic is interesting.

If it isn't true that I like math and I find the topic of logic interesting, then I miss class.

If the topic of logic is interesting and I do not miss class, then I like math.

If I miss class, then I don't like math or the topic of logic is not interesting.

If I miss class, then it isn't true that I like math and the topic of logic is interesting.

I do not miss class if and only if the topic of logic is interesting and I like math.

I like math if and only if the topic of logic is interesting, and I do not miss class.

If I miss class then the topic of logic is not interesting, or I like math.

If I like math and the topic of logic is interesting, then I do not miss class.

I like math, and if the topic of logic is interesting, then I do not miss class.  

Solution

Let's match the compound statements to their symbolic forms:

  1. "I do not miss class if and only if I like math and the topic of logic is interesting."

    • This statement implies a bi-conditional relationship between not missing class and both liking math and finding the topic of logic interesting.
    • Symbolic form: r ↔ (p ∧ q)
  2. "If it isn't true that I like math and I find the topic of logic interesting, then I miss class."

    • This statement expresses that the negation of "I like math and find the topic of logic interesting" leads to missing class.
    • Symbolic form: ∼(p ∧ q) → ∼r
  3. "If the topic of logic is interesting and I do not miss class, then I like math."

    • This statement implies that both the topic of logic being interesting and not missing class lead to liking math.
    • Symbolic form: (q ∧ ∼r) → p
  4. "If I miss class, then I don't like math or the topic of logic is not interesting."

    • This is an implication stating that missing class leads to either not liking math or the topic of logic not being interesting.
    • Symbolic form: ∼r → ∼p ∨ ∼q
  5. "If I miss class, then it isn't true that I like math and the topic of logic is interesting."

    • This statement suggests that missing class implies the negation of both liking math and the topic of logic being interesting.
    • Symbolic form: ∼r → ∼(p ∧ q)
  6. "I do not miss class if and only if the topic of logic is interesting and I like math."

    • This is essentially the reverse of the first statement, expressing a bi-conditional between not missing class and both liking math and the topic being interesting.
    • Symbolic form: ∼r ↔ (p ∧ q)
  7. "I like math if and only if the topic of logic is interesting, and I do not miss class."

    • This implies a bi-conditional between liking math and the topic of logic being interesting, along with not missing class.
    • Symbolic form: (p ↔ q) ∧ ∼r
  8. "If I miss class, then the topic of logic is not interesting, or I like math."

    • This is an implication where missing class leads to either the topic of logic not being interesting or liking math.
    • Symbolic form: ∼r → ∼q ∨ p
  9. "If I like math and the topic of logic is interesting, then I do not miss class."

    • This is an implication where both liking math and the topic of logic being interesting lead to not missing class.
    • Symbolic form: (p ∧ q) → ∼r
  10. "I like math, and if the topic of logic is interesting, then I do not miss class."

    • This is a conjunction of liking math and an implication that the topic of logic being interesting leads to not missing class.
    • Symbolic form: p ∧ (q → ∼r)

Summary of matches:

  1. r ↔ (p ∧ q)
  2. ∼(p ∧ q) → ∼r
  3. (q ∧ ∼r) → p
  4. ∼r → ∼p ∨ ∼q
  5. ∼r → ∼(p ∧ q)
  6. ∼r ↔ (p ∧ q)
  7. (p ↔ q) ∧ ∼r
  8. ∼r → ∼q ∨ p
  9. (p ∧ q) → ∼r
  10. p ∧ (q → ∼r)

Would you like further explanation on any of these?


Related questions:

  1. How do you prove the equivalence of two compound statements?
  2. What is the difference between a conjunction and a disjunction in logic?
  3. How can you use truth tables to verify logical statements?
  4. What is the significance of a bi-conditional (↔) in logic?
  5. Can logical implications be rewritten in terms of disjunctions?

Tip:

In logic, always break down complex compound statements into simpler components to better understand the relationships between them. This often makes it easier to translate them into symbolic form.

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Math Problem Analysis

Mathematical Concepts

Logic
Propositional Logic
Compound Statements
Symbolic Logic

Formulas

(p ∧ q) → r
p ∧ (q → r)
(∼r → ∼q) ∨ p
(q ∧ r) → p
r ↔ q ∧ p
∼r → ∼(p ∧ q)
∼(p ∧ q) → ∼r
r ↔ p ∧ q
∼r → ∼p ∨ ∼q
(p ↔ q) ∧ r

Theorems

Implication
Conjunction
Disjunction
Bi-conditional
Negation

Suitable Grade Level

Grades 11-12