Math Problem Statement

COMPOUND INTEREST

Use I = (P × (1 + R/N)NT) – P and A = (P × (1 + R/N)NT) to solve these compound interest problems. Remember that financial answers should be rounded to the nearest hundredth.

  1. Suzanne is looking at taking out a personal loan. Opportunity Loans is offering her $1600 at 3.45% for 1 year, with interest compounding monthly. General Loans is offering her $1600 at 4.2% for 1 year, with interest compounding quarterly. Assuming she makes no payments until the 1 year is up, how much interest will have accrued on each loan? On which loan will she earn the least amount of interest?

Opportunity Loans = $Answer 1 Question 4 in accrued interest.

General Loans = $Answer 2 Question 4 in accrued interest.

The loan from Answer 3 Question 4 Opportunity Loans will earn the least amount of interest.

  1. General. Gavin wants to put $3,475 into a savings account when his daughter is born. Examine the account options below to determine which will have a higher accrued value at the end of 5 years.
    

Community Bank

1.90%

Compounds daily

Capital Bank

2.05%

Compounds monthly

The loan from Community Bank will accrue $Answer 4 Question 4

The loan from Capital Bank will accrue Answer 5 Question 4 .

The loan from Answer 6 Question 4 Capital Bank will have a higher accrued value after 5 years.

Solution

Let's solve each problem step by step using the formulas provided.

Problem 1: Suzanne's Personal Loan

Formulas:

  • Interest Accrued: I=P×(1+RN)NTPI = P \times \left(1 + \frac{R}{N}\right)^{NT} - P
  • Accrued Amount: A=P×(1+RN)NTA = P \times \left(1 + \frac{R}{N}\right)^{NT}

Where:

  • PP = Principal amount (initial loan amount)
  • RR = Annual interest rate (as a decimal)
  • NN = Number of compounding periods per year
  • TT = Time the money is invested or borrowed for (in years)

Opportunity Loans:

  • P=1600P = 1600
  • R=3.45%=0.0345R = 3.45\% = 0.0345
  • N=12N = 12 (monthly compounding)
  • T=1T = 1 year

Using the interest formula: I=1600×(1+0.034512)12×11600I = 1600 \times \left(1 + \frac{0.0345}{12}\right)^{12 \times 1} - 1600

Let's calculate this:

I=1600×(1+0.002875)121600I = 1600 \times \left(1 + 0.002875\right)^{12} - 1600 I=1600×(1.035106)1600I = 1600 \times \left(1.035106\right) - 1600 I=1600×1.0351061600I = 1600 \times 1.035106 - 1600 I=1656.171600I = 1656.17 - 1600 I=56.17I = 56.17

Opportunity Loans Interest: $56.17

General Loans:

  • P=1600P = 1600
  • R=4.2%=0.042R = 4.2\% = 0.042
  • N=4N = 4 (quarterly compounding)
  • T=1T = 1 year

Using the interest formula: I=1600×(1+0.0424)4×11600I = 1600 \times \left(1 + \frac{0.042}{4}\right)^{4 \times 1} - 1600

Let's calculate this:

I=1600×(1+0.0105)41600I = 1600 \times \left(1 + 0.0105\right)^{4} - 1600 I=1600×(1.042832)1600I = 1600 \times \left(1.042832\right) - 1600 I=1668.531600I = 1668.53 - 1600 I=68.53I = 68.53

General Loans Interest: $68.53

Comparison:

  • Least Interest: Suzanne will earn the least interest with Opportunity Loans ($56.17).

Problem 2: Gavin's Savings Account

Community Bank:

  • P=3475P = 3475
  • R=1.90%=0.019R = 1.90\% = 0.019
  • N=365N = 365 (daily compounding)
  • T=5T = 5 years

Using the accrued amount formula: A=3475×(1+0.019365)365×5A = 3475 \times \left(1 + \frac{0.019}{365}\right)^{365 \times 5}

Let's calculate this:

A=3475×(1+0.00005205)1825A = 3475 \times \left(1 + 0.00005205\right)^{1825} A=3475×(1.098388)A = 3475 \times \left(1.098388\right) A=3818.15A = 3818.15

Community Bank Accrued Value: $3818.15

Capital Bank:

  • P=3475P = 3475
  • R=2.05%=0.0205R = 2.05\% = 0.0205
  • N=12N = 12 (monthly compounding)
  • T=5T = 5 years

Using the accrued amount formula: A=3475×(1+0.020512)12×5A = 3475 \times \left(1 + \frac{0.0205}{12}\right)^{12 \times 5}

Let's calculate this:

A=3475×(1+0.00170833)60A = 3475 \times \left(1 + 0.00170833\right)^{60} A=3475×(1.106507)A = 3475 \times \left(1.106507\right) A=3844.63A = 3844.63

Capital Bank Accrued Value: $3844.63

Comparison:

  • Higher Accrued Value: The Capital Bank account will have the higher accrued value after 5 years ($3844.63).

Summary:

  1. Opportunity Loans Interest Accrued: $56.17
  2. General Loans Interest Accrued: $68.53
  3. Least Interest Loan: Opportunity Loans
  4. Community Bank Accrued Value: $3818.15
  5. Capital Bank Accrued Value: $3844.63
  6. Higher Accrued Value: Capital Bank

Would you like more details or have any questions?

Related Questions:

  1. How does increasing the compounding frequency affect the interest accrued on a loan?
  2. What is the impact of a longer loan term on the total interest accrued?
  3. How do different interest rates affect the decision to choose between two savings accounts?
  4. How would semi-annual compounding compare to monthly compounding for these loans?
  5. What happens to the accrued interest if Suzanne decides to pay off the loan early?

Tip: When comparing financial options, always consider both the interest rate and the compounding frequency, as these can significantly affect the final amount of interest or accrued value.

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Math Problem Analysis

Mathematical Concepts

Compound Interest
Interest Formulas
Financial Mathematics

Formulas

Compound Interest formula: A = P * (1 + R/N)^(NT)
Interest Accrued formula: I = P * ((1 + R/N)^(NT) - 1)

Theorems

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Suitable Grade Level

High School