Math Problem Statement

(Compound value​) Stanford​ Simmons, who recently sold his​ Porsche, placed ​$10 comma 000 in a savings account paying annual compound interest of 6 percent. a. Calculate the amount of money that will have accrued if he leaves the money in the bank for 1​, 5​, and 15 years. b. If he moves his money into an account that pays 8 percent or one that pays 10 ​percent, rework part a using these new interest rates. c. What conclusions can you draw about the relationship between interest​ rates, time, and future sums from the calculations you have completed in this​ problem? Question content area bottom Part 1 a. What is the accrued value of ​$10 comma 000 in a savings account paying annual compound interest of 6 percent for 1 ​year? ​$    10600  ​(Round to the nearest​ cent.) Part 2 What is the accrued value of ​$10 comma 000 in a savings account paying annual compound interest of 6 percent for 5 ​years? ​$    13382.26  ​(Round to the nearest​ cent.) Part 3 What is the accrued value of ​$10 comma 000 in a savings account paying annual compound interest of 6 percent for 15 ​years?

Solution

To calculate the accrued value of an investment with compound interest, we use the formula:

A=P(1+rn)ntA = P \left( 1 + \frac{r}{n} \right)^{nt}

Where:

  • AA is the amount of money accumulated after tt years, including interest.
  • PP is the principal amount (the initial money invested).
  • rr is the annual interest rate (decimal form).
  • nn is the number of times the interest is compounded per year. Since the interest is compounded annually, n=1n = 1.
  • tt is the number of years.

For this question:

  • P=10,000P = 10,000
  • r=6%=0.06r = 6\% = 0.06
  • n=1n = 1 (since interest is compounded annually)

Part 1: Accrued Value after 1 Year

A=10,000(1+0.061)1×1A = 10,000 \left( 1 + \frac{0.06}{1} \right)^{1 \times 1} A=10,000×(1.06)1=10,600A = 10,000 \times (1.06)^1 = 10,600

So, the accrued value after 1 year is $10,600.

Part 2: Accrued Value after 5 Years

A=10,000(1+0.061)1×5A = 10,000 \left( 1 + \frac{0.06}{1} \right)^{1 \times 5} A=10,000×(1.06)5=10,000×1.338225=13,382.26A = 10,000 \times (1.06)^5 = 10,000 \times 1.338225 = 13,382.26

So, the accrued value after 5 years is $13,382.26.

Part 3: Accrued Value after 15 Years

A=10,000(1+0.061)1×15A = 10,000 \left( 1 + \frac{0.06}{1} \right)^{1 \times 15} A=10,000×(1.06)15=10,000×2.396856=23,968.56A = 10,000 \times (1.06)^{15} = 10,000 \times 2.396856 = 23,968.56

So, the accrued value after 15 years is $23,968.56.


Would you like me to move on to parts b and c of the problem and compute the new accrued values for interest rates of 8% and 10%?

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Math Problem Analysis

Mathematical Concepts

Compound Interest
Exponential Growth
Financial Mathematics

Formulas

A = P (1 + r/n)^(nt)

Theorems

Compound Interest Theorem

Suitable Grade Level

Grades 9-12