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The problem states that a farmer has deposited Rp100,000,000.00 in a bank with a compound interest rate of 0.6% per quarter for 3 years. We need to find the total interest earned after 3 years.

### Step-by-Step Solution:

1. **Identify Variables:**
   - Principal (P) = Rp100,000,000.00
   - Interest rate per quarter (r) = 0.6% = 0.006
   - Number of quarters in 3 years = \( n = 3 \text{ years} \times 4 \text{ quarters/year} = 12 \)

2. **Compound Interest Formula:**
   \[
   A = P \times (1 + r)^n
   \]
   where \( A \) is the amount after time \( n \).

3. **Calculate the Final Amount (A):**
   \[
   A = 100,000,000 \times (1 + 0.006)^{12}
   \]

4. **Calculate Total Interest:**
   \[
   \text{Total Interest} = A - P
   \]

Let's compute this.The final amount after 3 years is approximately Rp107,442,416.77. The total interest earned after 3 years is around Rp7,442,416.77.

Would you like more details or have any questions? Here are some related questions:

1. How would the total interest change if the interest rate increased to 1% per quarter?
2. What would be the total amount if the money was withdrawn after 2 years instead of 3?
3. How is compound interest different from simple interest in this scenario?
4. What is the effective annual interest rate in this case?
5. If the interest was compounded monthly instead of quarterly, what would be the total interest?

**Tip:** When dealing with compound interest, it's important to know the compounding frequency as it significantly affects the total interest earned.

Seorang petani mendapatkan uang sebesar Rp100.000.000,00 dari hasil panen selama 6 bulan. Ia menyimpan uang tersebut di sebuah bank yang menerapkan bunga majemuk 0,6% per cawu dan uang tersebut akan diambil setelah 3 tahun. Jumlah bunga setelah 3 tahun adalah...

Learn how to calculate compound interest for an initial investment of Rp100,000,000 with a 0.6% quarterly interest rate over 3 years. This detailed solution walks you through step-by-step calculations using the compound interest formula, suitable for Grades 10-12.

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