Math Problem Statement
In the year 2008, a company made $3.5 million in profit. For each consecutive year after that, their profit increased by 13%. How much would the company's profit be in the year 2010, to the nearest tenth of a million dollars?
Solution
To calculate the company's profit in the year 2010, we will use the concept of compound growth, where the profit increases by 13% each year after 2008.
Step 1: Set up the formula for compound growth.
The formula for compound growth is: Where:
- is the initial profit (in 2008), which is $3.5 million.
- is the rate of growth per year, which is 13% or 0.13.
- is the number of years after 2008 (so for 2010, ).
- is the profit in the year we are calculating.
Step 2: Plug in the values.
We need to find the profit in 2010, which is 2 years after 2008. So:
Step 3: Round the answer.
To the nearest tenth of a million dollars, the profit in 2010 is approximately:
So, the company's profit in 2010 is $4.5 million.
Would you like more details or have any further questions? Here are 5 related questions you might find interesting:
- How would the profit look in 2015, 7 years after 2008?
- If the company had a 10% increase instead of 13%, how would that change the 2010 profit?
- What would the company’s profit be in 2010 if the growth rate were compounded monthly?
- How could this model be adjusted for a situation with varying annual growth rates?
- What other types of growth models might be applicable in this scenario, besides compound growth?
Tip: Compound growth can make a large impact over time, so even small percentage increases can lead to significant gains over multiple years.
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Math Problem Analysis
Mathematical Concepts
Compound Growth
Exponential Growth
Formulas
P = P0(1 + r)^t
Theorems
Compound Growth Formula
Suitable Grade Level
Grades 8-10
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